2. Design a canal syphon for the following data:
Canal: Drainage:
Full supply discharge = 50 cumees Catchment area = 65 km2
| Full supply level = 202.30 Dicken’s coefficient = 5.0
Canal bed level = 200.00 Bed level = 201.00
Canal bed width = 20 m High flood level = 203.50
C Sideslopes=0H:IV
4 me other data, if required.
a L
=
nl
Question:
2. Design a canal syphon for the following data:
Canal: Drainage:
Full supply discharge = 50 cumees Catchment area = 65 km2
| Full supply level = 202.30 Dicken’s coefficient = 5.0
Canal bed level = 200.00 Bed level = 201.00
Canal bed width = 20 m High flood level = 203.50
C Sideslopes=0H:IV
4 me other data, if required.
a L
=
nl
This is AI generated Response.
Asked by: Test User 100005
Created at: 2025-05-11 22:06:27
Final Answer:
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Let's break down the design of a **canal syphon** for the given data step-by-step.
---
## **1. Given Data**
### **Canal:**
- **Full supply discharge (Q_canal):** 50 cumecs
- **Full supply level (FSL):** 202.30 m
- **Canal bed level:** 200.00 m
- **Canal bed width (b):** 20 m
- **Side slopes:** 0.5 H : 1 V
### **Drainage:**
- **Catchment area (A):** 65 km²
- **Dicken’s coefficient (C):** 5.0
- **Bed level:** 201.00 m
- **High flood level:** 203.50 m
---
## **2. Estimation of Drainage Discharge**
Using Dicken’s Formula:
\[
Q_{drainage} = C \times A^{3/4}
\]
Where:
- \( C = 5.0 \)
- \( A = 65\,km^2 \)
\[
Q_{drainage} = 5.0 \times (65)^{3/4}
\]
Calculate \( 65^{3/4} \):
\[
\ln(65) \approx 4.174387
\]
\[
3/4 \times 4.174387 = 3.13079
\]
\[
e^{3.13079} \approx 22.88
\]
\[
Q_{drainage} = 5 \times 22.88 \approx 114.4\,m^3/s
\]
---
## **3. Determination of Syphon Barrel Size**
The syphon barrels must carry the canal discharge (50 cumecs) **under** the drainage channel.
### **a) Canal Cross-section at the Syphon**
Assume the same section as canal:
- Bed width \( b = 20\,m \)
- Side slopes \( m = 0.5 \)
- Let water depth = \( h \)
Area, \( A \):
\[
A = b \cdot h + m \cdot h^2
\]
\[
A = 20h + 0.5h^2
\]
Given:
\[
Q = A \cdot V
\]
Let’s assume permissible velocity \( V = 2.0\,m/s \) (typical for barrel flow).
\[
A = \frac{Q}{V} = \frac{50}{2.0} = 25\,m^2
\]
So,
\[
20h + 0.5h^2 = 25
\]
\[
0.5h^2 + 20h - 25 = 0
\]
Solve quadratic:
\[
h = \frac{ -20 \pm \sqrt{400 - 4 \times 0.5 \times (-25)}}{2 \times 0.5}
\]
\[
= \frac{-20 \pm \sqrt{400 + 50}}{1}
\]
\[
= -20 \pm \sqrt{450}
\]
\[
\sqrt{450} \approx 21.21
\]
\[
h = -20 + 21.21 = 1.21\,m
\]
### **b) Number and Size of Barrels**
Let’s use a rectangular barrel of width \( w \) and height \( h \):
- Assume barrel width = 3 m (standard), height = 3 m.
Area per barrel = \( 3 \times 3 = 9\,m^2 \)
Number of barrels required:
\[
\text{Number of barrels} = \frac{25}{9} \approx 2.78 \implies 3 \text{ barrels}
\]
Provide **3 barrels** each of 3 m x 3 m.
---
## **4. Hydraulic Design Checks**
- **Inlet and Outlet Levels:**
- Canal FSL: 202.30 m
- Canal Bed: 200.00 m
- Drainage Bed: 201.00 m
- Drainage HFL: 203.50 m
- **Syphon invert level:**
Should be kept **below drainage bed** (say, 0.5 m below = 200.50 m).
---
## **5. Summary of Design**
### **Canal Syphon Design:**
- **Number of barrels:** 3
- **Size of each barrel:** 3 m x 3 m (rectangular)
- **Invert level of barrel:** 200.50 m
- **Barrel length:** As per width of drainage plus side slopes (estimate as per site, e.g., 30 m)
- **Material:** RCC or as per standard practice
### **Other Details:**
- **Head losses** to be checked (entrance, friction, exit losses)
- **Structural design** of barrels (not covered in this summary)
---
### **Assumptions:**
- Permissible velocity in barrel: 2.0 m/s
- No silt or debris problem assumed
- Freeboard and other structural details as per standard codes
---
If you need calculations for head loss or a sketch, let me know!
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