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2 . Consider the loan application office example we modeled in lab classes. There are 4 different processes which are 1 ) Credit check 2 ) Preparing the loan covenant 3 ) Pricing the loan 4 ) Disbursement of funds Bank manager should decide whether to have specialized serial or generalized parallel workers when processing involves the above tasks. There are 4 workers. The performance measure that bank manager considered is mean response time per customer. In order to find difference between two processing, two models are run with the service times that are generated with independent random numbers, common random numbers with synchronization and common random numbers without synchronization. The average service time for serial and parallel workers models are given below as Model 1 and Model 2 respectively. Replication 1 2 3 4 5 6 7 8 9 1 0 Average Response Time for Model ( minutes ) Model 2 CRN Model 2 CRN Model 1 Model 2 IRN w / Sync w / o Sync . 2 4 . 8 2 1 7 . 1 1 8 . 6 3 2 2 . 7 9 4 4 . 2 8 1 5 . 6 7 9 . 8 6 2 4 . 2 3 2 7 . 3 1 4 . 0 8 1 6 . 4 1 2 1 . 2 4 1 9 . 4 2 1 1 . 3 6 8 . 9 0 1 5 . 7 2 3 4 . 9 4 1 1 . 7 1 1 9 . 6 3 2 2 . 5 4 4 6 . 7 1 1 1 . 6 6 1 7 . 5 7 1 7 . 7 8 4 5 . 8 9 1 7 . 4 2 1 8 . 3 2 2 0 . 6 9 3 1 . 3 1 2 . 5 8 1 3 . 1 3 1 3 . 7 7 2 6 . 7 7 9 . 8 1 0 . 4 6 2 3 . 7 7 2 2 . 7 9 1 7 . 1 5 1 3 . 6 2 2 3 . 8 5 a . Compare the serial and parallel loan application processing using independent sampling and CRN where R - R . - R . Please comment about the results you find. b . Determine how many replications are needed if it is important to detect difference of 4 minutes per customer. give full answer and give final summary

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2 . Consider the loan application office example we modeled in lab classes. There are 4 different processes which are 1 ) Credit check 2 ) Preparing the loan covenant 3 ) Pricing the loan 4 ) Disbursement of funds Bank manager should decide whether to have specialized serial or generalized parallel workers when processing involves the above tasks. There are 4 workers. The performance measure that bank manager considered is mean response time per customer. In order to find difference between two processing, two models are run with the service times that are generated with independent random numbers, common random numbers with synchronization and common random numbers without synchronization. The average service time for serial and parallel workers models are given below as Model 1 and Model 2 respectively. Replication 1 2 3 4 5 6 7 8 9 1 0 Average Response Time for Model ( minutes ) Model 2 CRN Model 2 CRN Model 1 Model 2 IRN w / Sync w / o Sync . 2 4 . 8 2 1 7 . 1 1 8 . 6 3 2 2 . 7 9 4 4 . 2 8 1 5 . 6 7 9 . 8 6 2 4 . 2 3 2 7 . 3 1 4 . 0 8 1 6 . 4 1 2 1 . 2 4 1 9 . 4 2 1 1 . 3 6 8 . 9 0 1 5 . 7 2 3 4 . 9 4 1 1 . 7 1 1 9 . 6 3 2 2 . 5 4 4 6 . 7 1 1 1 . 6 6 1 7 . 5 7 1 7 . 7 8 4 5 . 8 9 1 7 . 4 2 1 8 . 3 2 2 0 . 6 9 3 1 . 3 1 2 . 5 8 1 3 . 1 3 1 3 . 7 7 2 6 . 7 7 9 . 8 1 0 . 4 6 2 3 . 7 7 2 2 . 7 9 1 7 . 1 5 1 3 . 6 2 2 3 . 8 5 a . Compare the serial and parallel loan application processing using independent sampling and CRN where R - R . - R . Please comment about the results you find. b . Determine how many replications are needed if it is important to detect difference of 4 minutes per customer. give full answer and give final summary

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Asked by: Dinil
Created at: 2026-01-08 01:09:38

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# Comparison of Serial vs Parallel Loan Application Processing This analysis compares **serial (specialized)** and **parallel (generalized)** processing models for a bank's loan application system. There are 4 workers and 4 tasks: 1. Credit check 2. Preparing the loan covenant 3. Pricing the loan 4. Disbursement of funds The performance measure is **mean response time per customer**. Simulations were run using: - **Model 1:** Serial processing - **Model 2:** Parallel processing - **IRN:** Independent Random Numbers - **CRN (w/ Sync):** Common Random Numbers, with synchronization - **CRN (w/o Sync):** Common Random Numbers, without synchronization The table below summarizes 10 replications of average response times (minutes): | Replication | Model 1 | Model 2 IRN | Model 2 CRN w/Sync | Model 2 CRN w/o Sync | |-------------|---------|-------------|--------------------|----------------------| | 1 | 24.82 | 17.13 | 18.63 | 22.79 | | 2 | 44.28 | 15.67 | 9.86 | 14.08 | | 3 | 24.23 | 27.3 | 16.41 | 21.24 | | 4 | 19.42 | 11.36 | 8.90 | 15.72 | | 5 | 34.94 | 11.71 | 19.63 | 22.54 | | 6 | 46.71 | 11.66 | 17.57 | 17.78 | | 7 | 45.89 | 17.42 | 18.32 | 20.69 | | 8 | 31.3 | 12.58 | 13.13 | 13.77 | | 9 | 26.77 | 9.8 | 10.46 | 23.77 | | 10 | 22.79 | 17.15 | 13.62 | 23.85 | --- ## a. Comparison and Comments ### Mean Response Times Let's calculate the mean response times for each model: ```markdown Mean(Model 1) = (24.82 + 44.28 + 24.23 + 19.42 + 34.94 + 46.71 + 45.89 + 31.3 + 26.77 + 22.79) / 10 ≈ 32.215 min Mean(Model 2 IRN) = (17.13 + 15.67 + 27.3 + 11.36 + 11.71 + 11.66 + 17.42 + 12.58 + 9.8 + 17.15) / 10 ≈ 15.978 min Mean(Model 2 CRN w/Sync) = (18.63 + 9.86 + 16.41 + 8.90 + 19.63 + 17.57 + 18.32 + 13.13 + 10.46 + 13.62) / 10 ≈ 14.753 min Mean(Model 2 CRN w/o Sync) = (22.79 + 14.08 + 21.24 + 15.72 + 22.54 + 17.78 + 20.69 + 13.77 + 23.77 + 23.85) / 10 ≈ 19.923 min ``` ### Observations - **Parallel (Model 2) is consistently faster** than Serial (Model 1) under all random number schemes. - Using **CRN with synchronization** slightly reduces variability and mean response time, compared to independent random numbers. - **CRN without synchronization** results in higher mean response time and more variability compared to CRN with sync, but still outperforms serial processing. - **Serial processing (Model 1)** has a much higher mean response time and greater variability, indicating a bottleneck effect typical of serial queues. ### Statistical Efficiency - Using **common random numbers (CRN)** allows for paired comparisons and reduces variance of the difference between models, making statistical tests more powerful. - **Synchronization** of random numbers further enhances this effect. --- ## b. Required Number of Replications Suppose the goal is to **detect a difference of 4 minutes in mean response time per customer**. ### Steps 1. **Estimate the standard deviation (s) of the paired differences** between serial and parallel models (using CRN with sync for highest efficiency). 2. Use the formula for the required number of replications for a two-sided confidence interval: \[ n = \left( \frac{z_{\alpha/2} \cdot s}{\delta} \right)^2 \] where: - \(z_{\alpha/2}\) = 1.96 for 95% confidence - \(s\) = sample standard deviation of the paired differences - \(\delta\) = minimum detectable difference (4 minutes) #### Calculate Paired Differences (Serial - Parallel, CRN with Sync) | Replication | Serial (M1) | Parallel (M2 CRN w/Sync) | Difference | |-------------|-------------|--------------------------|------------| | 1 | 24.82 | 18.63 | 6.19 | | 2 | 44.28 | 9.86 | 34.42 | | 3 | 24.23 | 16.41 | 7.82 | | 4 | 19.42 | 8.90 | 10.52 | | 5 | 34.94 | 19.63 | 15.31 | | 6 | 46.71 | 17.57 | 29.14 | | 7 | 45.89 | 18.32 | 27.57 | | 8 | 31.3 | 13.13 | 18.17 | | 9 | 26.77 | 10.46 | 16.31 | | 10 | 22.79 | 13.62 | 9.17 | Calculate the sample mean and standard deviation \(s\): \[ \text{Mean} = \frac{6.19 + 34.42 + 7.82 + 10.52 + 15.31 + 29.14 + 27.57 + 18.17 + 16.31 + 9.17}{10} = 17.962 \] \[ s = \sqrt{ \frac{1}{n-1} \sum_{i=1}^{n} (d_i - \bar{d})^2 } \] Calculating each squared difference and the sum: - (6.19 - 17.962)^2 = 139.07 - (34.42 - 17.962)^2 = 269.17 - (7.82 - 17.962)^2 = 103.23 - (10.52 - 17.962)^2 = 55.50 - (15.31 - 17.962)^2 = 7.02 - (29.14 - 17.962)^2 = 124.79 - (27.57 - 17.962)^2 = 92.47 - (18.17 - 17.962)^2 = .04 - (16.31 - 17.962)^2 = 2.73 - (9.17 - 17.962)^2 = 77.25 Sum = 871.27 \[ s = \sqrt{ \frac{871.27}{9} } = \sqrt{96.81} \approx 9.84 \] #### Plug into the formula \[ n = \left( \frac{1.96 \cdot 9.84}{4} \right)^2 = \left( \frac{19.27}{4} \right)^2 = (4.8175)^2 \approx 23.23 \] **Thus, about 24 replications** are needed to detect a 4-minute difference at 95% confidence. --- # Final Summary - **Parallel (generalized) processing significantly outperforms serial (specialized) processing** in terms of mean response time for the loan application system, regardless of the random number scheme used. - **Using common random numbers (CRN), especially with synchronization, reduces variance and allows for more precise comparison** between models. - To reliably detect a 4-minute difference in mean response time per customer at the 95% confidence level, **approximately 24 replications** are required under the current observed variability. - The data strongly supports using a parallel model with CRN synchronization for both operational efficiency and experimental analysis. --- **Note:** - For real-world implementation, the bank manager should consider not just mean performance but also variability, process robustness, and other operational constraints. - The analysis assumes the validity of the simulation model and independence between customers. - Further analysis could examine resource utilization and cost implications.

Question:

give 2 sentence for each steps A and B

This is AI generated Response.
Asked by: Dinil
Created at: 2026-01-08 01:10:23

Final Answer:

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# A. Comparison and Comments The analysis reveals that **parallel processing (Model 2)** consistently yields lower mean response times than **serial processing (Model 1)** across all sampling methods. This indicates that a parallel approach is more efficient, as it minimizes bottlenecks and enhances operational throughput. ### Summary for A - Parallel processing outperforms serial processing in average response times, emphasizing the efficiency of simultaneous task execution. - The use of common random numbers, especially with synchronization, enhances the reliability of the results and reduces variability in response times. --- # B. Required Number of Replications To detect a difference of 4 minutes in mean response time with 95% confidence, approximately **24 replications** are required based on the observed data variability. This ensures a statistically valid comparison, allowing for an effective assessment of the differences between the processing models. ### Summary for B - The calculated number of replications needed to identify a significant difference provides a quantitative basis for experimental design. - Ensuring this number of replications will enhance the robustness of the conclusions drawn from the loan processing performance analysis.

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