Act like a helpful tutor and exlain me :
Give step-by-step solution with explanation and final answer:
give answer in englishAREA HA il i
(ARN i fH
pH fl AHR Tiempo restante 0:06:49
ACR RA EIA
AERA TARA |
ANA AMERANE J Lm
530 cfm de aire que proviene del exterior se mezclara con 1550 cfm de aire que retornan del local, £1
local se encuentra a 75 of ¥ 66 °F bh; el aire exterior se encuentra a 95 oF ¥ 78 °F bh; el aire que sale
dela lnidad fcondicionadora se encuentra a 57 “Fly 86 % bh. Determine lo que se pide:
La cantidad de aire que sale en las mismas condiciones al pasar por la unidad acondicionadora, en’ Ly
cfm (considere que la temperatura superficial de la unidad acondicionadora es de 55 °F)
Question:
Act like a helpful tutor and exlain me :
Give step-by-step solution with explanation and final answer:
give answer in englishAREA HA il i
(ARN i fH
pH fl AHR Tiempo restante 0:06:49
ACR RA EIA
AERA TARA |
ANA AMERANE J Lm
530 cfm de aire que proviene del exterior se mezclara con 1550 cfm de aire que retornan del local, £1
local se encuentra a 75 of ¥ 66 °F bh; el aire exterior se encuentra a 95 oF ¥ 78 °F bh; el aire que sale
dela lnidad fcondicionadora se encuentra a 57 “Fly 86 % bh. Determine lo que se pide:
La cantidad de aire que sale en las mismas condiciones al pasar por la unidad acondicionadora, en’ Ly
cfm (considere que la temperatura superficial de la unidad acondicionadora es de 55 °F)
This is AI generated Response.
Asked by: manish kumar
Created at: 2025-09-16 21:40:48
Final Answer:
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Let's break down the **problem step by step** and solve it **in English**.
---
## **Problem Statement (English Translation)**
- **530 cfm** of outside air (at 95°F, 78° F bh) mixes with **1550 cfm** of return air from the room (at 75°F, 66°F bh).
- The air that leaves the air conditioning unit is at 57°F, 56°F bh.
- **Question:** How much air (cfm) exits the air conditioner **at the same conditions** as after passing through the unit, assuming the coil surface temperature is 55°F?
---
## **Step 1: Find the Total Mixed Airflow**
Total mixed air = outside air + return air
\[
Q_{mixed} = 530\, \text{cfm} + 1550\, \text{cfm} = 2080\, \text{cfm}
\]
---
## **Step 2: Understand the Question**
The question asks:
*How much air can be cooled to 57°F and 56°F bh (i.e., saturated or nearly saturated air at that condition), given the coil surface temperature is 55°F?*
This is a **bypass factor** or **coil ADP (Apparatus Dew Point)** problem.
---
## **Step 3: Find the Bypass Factor**
### **Bypass Factor (BF) Formula:**
\[
BF = \frac{T_{out} - T_{coil}}{T_{mix} - T_{coil}}
\]
Where:
- \( T_{out} \): Leaving air temperature = 57°F
- \( T_{coil} \): Coil surface temperature = 55°F
- \( T_{mix} \): Mixed air temperature (to be calculated)
---
## **Step 4: Calculate the Mixed Air Temperature (Tmix)**
\[
T_{mix} = \frac{(530 \times 95) + (1550 \times 75)}{2080}
\]
\[
T_{mix} = \frac{50350 + 116250}{2080} = \frac{166600}{2080} \approx 80.1^\circ F
\]
---
## **Step 5: Calculate the Bypass Factor**
\[
BF = \frac{57 - 55}{80.1 - 55} = \frac{2}{25.1} \approx 0.08
\]
---
## **Step 6: Find the Proportion of Air Cooled to Coil Temperature (55°F)**
The **portion of air actually cooled to coil temp** is:
\[
1 - BF = 1 - 0.08 = 0.92
\]
So, the **amount of air at 57°F and 56°F bh** is:
\[
\text{cfm}_{\text{leaving}} = \text{Total cfm} \times (1 - BF)
\]
\[
\text{cfm}_{\text{leaving}} = 2080 \times 0.92 = 1913.6\, \text{cfm}
\]
---
## **Final Answer**
### **The amount of air that leaves the air conditioning unit at 57°F and 56°F bh is:**
\[
\boxed{1914\ \text{cfm}}
\]
(**rounded to the nearest integer**)
---
### **Summary Table**
| Parameter | Value |
|----------------------|----------------|
| Mixed Airflow | 2080 cfm |
| Mixed Air Temp | 80.1°F |
| Coil Surface Temp | 55°F |
| Leaving Air Temp | 57°F |
| Bypass Factor | 0.08 |
| Leaving Air at 57°F | 1914 cfm |
Let me know if you need the psychrometric chart or further clarifications!
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