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Act like a helpful tutor and exlain me :Problem 12 Draw the profit and payoff diagrams for a cap, where you purchase a stock for $100, and short (sold) a call option, with strike K = 115, and call premium C' = 12%. Assume the continuously compounded risk-free interest rate is r = 5%.

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Act like a helpful tutor and exlain me :Uploaded ImageProblem 12 Draw the profit and payoff diagrams for a cap, where you purchase a stock for $100, and short (sold) a call option, with strike K = 115, and call premium C' = 12%. Assume the continuously compounded risk-free interest rate is r = 5%.

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Asked by: Alok Kumar
Created at: 2026-02-03 10:06:07

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## Problem 12 Explanation You are asked to **draw the profit and payoff diagrams** for a "cap" strategy, which consists of: - **Buying a stock at $100** - **Selling (shorting) a call option** with: - Strike price \( K = 115 \) - Call premium \( C = 12e^{-.05} \) - The risk-free rate \( r = 5\% \) (for discounting) Let's break down each component and then combine them. --- ### 1. **Payoff of Each Position at Expiry** #### **A. Stock Position** - **Payoff:** \( S_T \) (where \( S_T \) is the stock price at expiry) #### **B. Short Call Option** - **Payoff:** You sold the call, so your payoff is the negative of the call's payoff: - Call payoff: \( \max(, S_T - K) \) - Your payoff: \( -\max(, S_T - K) \) #### **C. Call Premium Received** - You receive \( C = 12e^{-.05} \) at time . To make the profit diagram at expiry, you should **compound this forward** to expiry: \[ C_{\text{future}} = 12e^{-.05} \cdot e^{.05} = 12 \] So, at expiry, you keep the full $12. --- ### 2. **Total Payoff and Profit Formulas** #### **A. Total Payoff (ignoring initial costs)** \[ \text{Total Payoff} = S_T - \max(, S_T - 115) \] - For \( S_T \leq 115 \): \( \text{Payoff} = S_T \) - For \( S_T > 115 \): \( \text{Payoff} = S_T - (S_T - 115) = 115 \) So, **the cap "flattens out" above $115**. #### **B. Total Profit** \[ \text{Profit} = \text{Payoff} + \text{Call Premium} - \text{Initial Stock Cost} \] \[ \text{Profit} = (\text{Payoff as above}) + 12 - 100 \] --- ### 3. **Summary Table** | \( S_T \) Range | Payoff | Profit | |------------------------|----------------|-----------------------| | \( S_T \leq 115 \) | \( S_T \) | \( S_T + 12 - 100 \) | | \( S_T > 115 \) | 115 | \( 115 + 12 - 100 = 27 \) | --- ### 4. **Diagrams** #### **A. Payoff Diagram** - **X-axis:** Stock price at expiry \( S_T \) - **Y-axis:** Payoff - **Line:** - For \( S_T \leq 115 \): Line with slope 1, starts at when \( S_T= \), reaches 115 at \( S_T=115 \). - For \( S_T > 115 \): Flat at 115. #### **B. Profit Diagram** - **X-axis:** Stock price at expiry \( S_T \) - **Y-axis:** Profit - **Line:** - For \( S_T \leq 115 \): Line with slope 1, intercepts Y-axis at \( -88 \) (since \( + 12 - 100 = -88 \)), reaches 27 at \( S_T=115 \). - For \( S_T > 115 \): Flat at 27. #### **Profit Diagram Sketch:** ``` Profit ($) ^ | 27|---------------------------- (flat for S_T > 115) | / | / | / -88|---------/ +-----------------------------> S_T 100 115 ``` --- ## **Summary** - The **cap strategy** gives unlimited profit up to \( S_T = 115 \) and then flatlines at $27 profit. - **Payoff**: Flat at $115 for \( S_T > 115 \), linear below. - **Profit**: Flat at $27 for \( S_T > 115 \), linear below. --- **Let me know if you'd like a matplotlib code or further explanation!**

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