VIPSolutions logo ✨ VIPSolutions

give full answer and give final summary[Vi Neher | on | olEaplores Sey Do | stay 0 Tandy 255 oboe | 30 pred hs 5 J | ssi * “To hot plc n ht al cpoycs we wo ve comctive dys pr eck wih tn Come eyo (Sry snd Soy om) Sac +

Question:

give full answer and give final summaryUploaded Image[Vi Neher | on | olEaplores Sey Do | stay 0 Tandy 255 oboe | 30 pred hs 5 J | ssi * “To hot plc n ht al cpoycs we wo ve comctive dys pr eck wih tn Come eyo (Sry snd Soy om) Sac +

This is AI generated Response.
Asked by: lincy
Created at: 2025-10-02 22:18:53

Final Answer:

Rendered Raw Text
Did you like this answer?
# Workforce Scheduling: Hotel Employees## Problem OverviewA hotel requires minimum number of employees on each day of the week (see table). Each employee works **five consecutive days** with **two consecutive days off**. Employees are paid **$120 per shift**, with a **$10 bonus** for working on Sundays. The objective is to **minimize total labor costs** while ensuring daily staffing requirements are met. | Day | Minimum Number of Employees | |------------|----------------------------| | Sunday | 330 | | Monday | 240 | | Tuesday | 255 | | Wednesday | 350 | | Thursday | 375 | | Friday | 335 | | Saturday | 360 | ## (a) Mathematical Formulation ### **Decision Variables** Let: - \( x_i \): Number of employees whose **first working day is day \( i \)** (where \( i = 1 \) to \( 7 \): 1=Sunday, 2=Monday, ..., 7=Saturday) ### **Objective Function** Minimize **total cost**: \[ \text{Total Cost} = 120 \times \text{Total shifts worked} + 10 \times \text{Total Sunday shifts} \] But since each employee works five shifts, with only those scheduled on Sunday receiving a $10 bonus for that day: \[ \text{Total Cost} = 120 \times 5 \times \sum_{i=1}^{7} x_i + 10 \times (\text{Number of employees working Sunday}) \] But since every employee works 5 days, and we only pay bonus for those working on Sunday, we need to count how many employees work on Sunday. Let’s note that anyone who **does not have Sunday or Saturday off** will work on Sunday. Let’s clarify with the schedule: - Employees starting on **Sunday**: work Sun, Mon, Tue, Wed, Thu - Employees starting on **Monday**: work Mon, Tue, Wed, Thu, Fri - Employees starting on **Tuesday**: work Tue, Wed, Thu, Fri, Sat - Employees starting on **Wednesday**: work Wed, Thu, Fri, Sat, Sun - Employees starting on **Thursday**: work Thu, Fri, Sat, Sun, Mon - Employees starting on **Friday**: work Fri, Sat, Sun, Mon, Tue - Employees starting on **Saturday**: work Sat, Sun, Mon, Tue, Wed #### Therefore, the number of employees working on Sunday = \( x_1 \) (start Sun) + \( x_4 \) (start Wed) + \( x_5 \) (start Thu) + \( x_6 \) (start Fri) + \(_7 \) (start Sat) So: \[ \text{Sunday Workers} = x_1 + x_4 + x_5 + x_6 + x_7 \] #### **Objective Function (Full):** \[ \text{Minimize } Z = 600 \sum_{i=1}^{7} x_i + 10(x_1 + x_4 + x_5 + x_6 + x_7) \] ### **Constraints** #### **Coverage Constraints** On each day, the sum of all employees scheduled to work that day must be at least the minimum required: Let’s define which variables cover each day: - **Sunday**: \( x_1 \) (start Sun), \( x_4 \) (start Wed), \( x_5 \) (start Thu), \( x_6 \) (start Fri), \( x_7 \) (start Sat) - **Monday**: \( x_1 \) (Sun), \( x_2 \) (Mon), \( x_5 \) (Thu), \( x_6 \) (Fri), \( x_7 \) (Sat) - **Tuesday**: \( x_1 \) (Sun), \( x_2 \) (Mon), \( x_3 \) (Tue), \( x_6 \) (Fri), \( x_7 \) (Sat) - **Wednesday**: \( x_1 \) (Sun), \( x_2 \) (Mon), \( x_3 \) (Tue), \( x_4 \) (Wed), \( x_7 \) (Sat) - **Thursday**: \( x_1 \) (Sun), \( x_2 \) (Mon), \( x_3 \) (Tue), \( x_4 \) (Wed), \( x_5 \) (Thu) - **Friday**: \( x_2 \) (Mon), \( x_3 \) (Tue), \( x_4 \) (Wed), \( x_5 \) (Thu), \( x_6 \) (Fri) - **Saturday**: \( x_3 \) (Tue), \( x_4 \) (Wed), \( x_5 \) (Thu), \( x_6 \) (Fri), \( x_7 \) (Sat) So, the constraints are: \[ \begin{align*} x_1 + x_4 + x_5 + x_6 + x_7 &\geq 330 \quad \text{(Sunday)} \\ x_1 + x_2 + x_5 + x_6 + x_7 &\geq 240 \quad \text{(Monday)} \\ x_1 + x_2 + x_3 + x_6 + x_7 &\geq 255 \quad \text{(Tuesday)} \\ x_1 + x_2 + x_3 + x_4 + x_7 &\geq 350 \quad \text{(Wednesday)} \\ x_1 + x_2 + x_3 + x_4 + x_5 &\geq 375 \quad \text{(Thursday)} \\ x_2 + x_3 + x_4 + x_5 + x_6 &\geq 335 \quad \text{(Friday)} \\ x_3 + x_4 + x_5 + x_6 + x_7 &\geq 360 \quad \text{(Saturday)} \\ \end{align*} \] #### **Non-negativity** \[ x_i \geq \quad \text{and integer, for } i = 1,...,7 \] --- ## (b) **Excel Model** Set up variables \( x_1 \) through \( x_7 \) in Excel, and use **Solver**: - **Objective:** Minimize \( 600 \times \text{SUM}(x_1:x_7) + 10 \times (x_1+x_4+x_5+x_6+x_7) \) - **Constraints:** As above (one for each day), and \( x_i \geq \), integer. --- ## (c) **LINGO Model** LINGO code: ```LINGO MODEL: SETS: DAYS /1..7/: x, req, sun_bonus; ENDSETS DATA: req = @TABLE( 1, 330, 2, 240, 3, 255, 4, 350, 5, 375, 6, 335, 7, 360 ); sun_bonus(1) = 1; sun_bonus(2) = ; sun_bonus(3) = ; sun_bonus(4) = 1; sun_bonus(5) = 1; sun_bonus(6) = 1; sun_bonus(7) = 1; ! Coverage matrix: work[i][j] = 1 if shift i covers day j; work(i,1) = @OR(i=1,i=4,i=5,i=6,i=7); work(i,2) = @OR(i=1,i=2,i=5,i=6,i=7); work(i,3) = @OR(i=1,i=2,i=3,i=6,i=7); work(i,4) = @OR(i=1,i=2,i=3,i=4,i=7); work(i,5) = @OR(i=1,i=2,i=3,i=4,i=5); work(i,6) = @OR(i=2,i=3,i=4,i=5,i=6); work(i,7) = @OR(i=3,i=4,i=5,i=6,i=7); ENDSETS ! Objective MIN = 600 * @SUM(DAYS(i): x(i)) + 10 * @SUM(DAYS(i): sun_bonus(i) * x(i)); ! Coverage constraints @FOR(DAYS(j): @SUM(DAYS(i): work(i,j) * x(i)) >= req(j) ); ! Integrality @FOR(DAYS(i): @GIN(x(i))); END ``` --- ## (d) **Recommendation** - **Interpret the solution:** The optimal values for \( x_1, ..., x_7 \) will give you the **number of employees to start on each day**. - This ensures minimum cost while meeting staffing requirements. - Employees should be scheduled according to the optimal start days as determined by the model. --- ## **Final Summary** - **Formulate as an integer linear program**: variables represent number of employees starting each day, objective is to minimize total labor + Sunday bonus. - **Implement in Excel or LINGO** using the model above. - **Recommendation:** Hire and schedule employees so that their start days match the optimal solution to minimize costs and ensure daily coverage. **(Actual numeric solution requires running the model in Excel or LINGO with real solvers.)**

📢 Instructions:

  • Ask anything relatd to above question only.
  • For new Question goto :

Study Help, Fast Answers

VIPSolutions focuses on clear, step‑by‑step explanations so you can learn quickly. Whether you need an AI‑generated walkthrough or a short hint to get unstuck, each solution is organized for fast reading and easy review later.

Search similar questions, compare approaches, and bookmark the best answers for revision. Our goal is simple: quick, reliable study help that feels natural—not noisy.