Give step-by-step solution with explanation and final answer:Pilot Parameter Unit
Tank diameter (D) 1 m
Tank height (H) 2 m
Loading factor 64 %
Impeller diameter (d) 0.5 m
Agitation speed 300 pm
Fermentation time 180 h
mes :
Gauge pressure of tank 0.3 MPa
Temperature in tank 28 °C
Aeration rate 12 VVM (standard conditions)
Broth viscosity 0.1 Pas
Broth density 1050 kg/m?
Final lipase concentration in broth ~~ 18.18 g/L
(5) Downstream Filtration
After each production-scale fermentation batch, the entire filtration operation for this batch must be
completed within 20 hours. Each filter press operates on a 2-hour cycle time.
The ratio of wet filter residue to feed liquid volume is known to be 30%. The filling coefficient
inside the filter frame is taken as 0.8. Determine the appropriate number of plate-and-frame
filter presses required. Use the model BAS20/635-25, with a total internal frame volume V =260 L.
(12 marks)
(6) Downstream ion-exchange purification
In the pilot system, a weak-acid resin ion-exchange column is used to adsorb the lipase solution at
an optimal flow rate of 1.2 m¥h. The pilot column has a bed height of 1.0 m and a diameter of 0.3 m.
For the production scale, the flow rate is set to 2.75 m*h, to ensure the entire ion-exchange step is
completed within 20 hours. Determine the height and diameter of the scaled-up ion-exchange
bed required, based on maintaining an equal linear velocity (®). (12 marks)
Question:
Give step-by-step solution with explanation and final answer:Pilot Parameter Unit
Tank diameter (D) 1 m
Tank height (H) 2 m
Loading factor 64 %
Impeller diameter (d) 0.5 m
Agitation speed 300 pm
Fermentation time 180 h
mes :
Gauge pressure of tank 0.3 MPa
Temperature in tank 28 °C
Aeration rate 12 VVM (standard conditions)
Broth viscosity 0.1 Pas
Broth density 1050 kg/m?
Final lipase concentration in broth ~~ 18.18 g/L
(5) Downstream Filtration
After each production-scale fermentation batch, the entire filtration operation for this batch must be
completed within 20 hours. Each filter press operates on a 2-hour cycle time.
The ratio of wet filter residue to feed liquid volume is known to be 30%. The filling coefficient
inside the filter frame is taken as 0.8. Determine the appropriate number of plate-and-frame
filter presses required. Use the model BAS20/635-25, with a total internal frame volume V =260 L.
(12 marks)
(6) Downstream ion-exchange purification
In the pilot system, a weak-acid resin ion-exchange column is used to adsorb the lipase solution at
an optimal flow rate of 1.2 m¥h. The pilot column has a bed height of 1.0 m and a diameter of 0.3 m.
For the production scale, the flow rate is set to 2.75 m*h, to ensure the entire ion-exchange step is
completed within 20 hours. Determine the height and diameter of the scaled-up ion-exchange
bed required, based on maintaining an equal linear velocity (®). (12 marks)
This is AI generated Response.
Asked by: francis
Created at: 2025-12-18 02:02:35
Final Answer:
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Let's solve **each question step-by-step** using the data provided.
---
# (5) **Downstream Filtration**
## **Given Data**
- **Tank diameter (D):** 1 m
- **Tank height (H):** 2 m
- **Loading factor:** 64%
- **Batch volume = Tank volume × Loading factor**
- **Operation time for filtration:** 20 h
- **Cycle time per filter press:** 2 h
- **Ratio of wet residue/filter cake to feed liquid volume:** 30% (i.e., for every 1 L of feed, .3 L of wet cake is produced)
- **Filling coefficient inside filter frame:** .8
- **Model BAS20/635-25:** total internal frame volume V = 260 L (per press, per cycle)
---
## **Step 1: Calculate the Batch Feed Volume**
### **Fermenter Working Volume**
\[
\text{Fermenter Volume} = \pi r^2 h = \pi \left(\frac{1}{2}\right)^2 \times 2 = \pi \times .25 \times 2 = \pi \times .5 \approx 1.57~\text{m}^3
\]
\[
\text{Loading Factor} = 64\%
\]
\[
\text{Working Volume} = 1.57 \times .64 \approx 1.01~\text{m}^3 = 101~\text{L}
\]
---
## **Step 2: Adjust for Wet Filter Cake**
\[
\text{Let } V = \text{feed liquid volume to filter}
\]
\[
\text{Wet Residue Volume} = .3V
\]
\[
\text{Total Volume to Fill Filter Frame} = \text{Wet Residue Volume}
\]
---
## **Step 3: Filter Press Frame Utilization per Cycle**
\[
\text{Effective Filter Frame Volume per Cycle (per press)} = .8 \times 260~\text{L} = 208~\text{L}
\]
---
## **Step 4: Number of Cycles Needed**
\[
\text{Wet filter cake to process per batch} = .3 \times 101 = 303~\text{L}
\]
Each press can process **208 L per cycle** (of cake).
\[
\text{Number of cycles required (per press)} = \frac{303}{208} \approx 1.46
\]
But, **each press cycle is 2 hours**, and the operation must be completed in **20 hours**.
\[
\text{Total cycles possible per press in 20 hours} = \frac{20}{2} = 10
\]
So, **one filter press can run 10 cycles in 20 hours**, processing:
\[
208~\text{L/cycle} \times 10~\text{cycles} = 208~\text{L}
\]
This is **much more** than required. But, the process must be completed in 20 hours, and the calculation above is for one batch (303 L of cake per batch).
\[
\text{Number of presses required} = \frac{1.46}{10} = .146
\]
But this value is **less than 1**, meaning **1 plate-and-frame filter press is sufficient**.
---
## **Final Answer for (5):**
### **Number of Plate-and-Frame Filter Presses Required**
\[
\boxed{1}
\]
**One BAS20/635-25 filter press is sufficient to complete the batch filtration within 20 hours.**
---
# (6) **Downstream Ion-Exchange Purification**
## **Given Data**
- **Pilot column:** Height = 1. m, Diameter = .3 m
- **Pilot flow rate:** 1.2 m³/h
- **Production flow rate:** 2.7 m³/h
- **Production step must finish in:** 20 h
- **Maintain same linear velocity (\( \omega \))**
---
## **Step 1: Calculate Linear Velocity in Pilot System**
\[
\text{Column cross-sectional area} = A = \pi r^2 = \pi \left(\frac{.3}{2}\right)^2 = \pi (.15)^2 \approx .0707~\text{m}^2
\]
\[
\text{Linear velocity } (\omega) = \frac{\text{Flow rate}}{\text{Area}} = \frac{1.2}{.0707} \approx 16.97~\text{m/h}
\]
---
## **Step 2: Calculate Required Area for Production Scale**
\[
\text{Required area} = \frac{\text{Production flow rate}}{\omega} = \frac{2.7}{16.97} \approx .1592~\text{m}^2
\]
---
## **Step 3: Choose Scaled Bed Height**
Pilot bed height = 1. m.
To finish in 20 h, the **bed volume must be sufficient for the batch**.
\[
\text{Batch volume to treat} = 101~\text{L} = 1.01~\text{m}^3
\]
But, since flow is 2.7 m³/h, in 20 h:
\[
\text{Total processed volume} = 2.7 \times 20 = 54~\text{m}^3
\]
But only **1.01 m³** is actually needed.
Since we're told to maintain linear velocity and scale area, we keep **height = 1. m**.
---
## **Step 4: Calculate Required Diameter**
\[
A = \pi \left(\frac{d}{2}\right)^2 = .1592~\text{m}^2
\]
\[
\frac{d}{2} = \sqrt{\frac{.1592}{\pi}} = \sqrt{.0507} \approx .225~\text{m}
\]
\[
d = 2 \times .225 = .45~\text{m}
\]
---
## **Final Answer for (6):**
### **Scaled Ion-Exchange Bed Dimensions**
- **Height:** \(\boxed{1.~\text{m}}\)
- **Diameter:** \(\boxed{.45~\text{m}}\)
---
## **Summary Table**
| Part | Final Answer |
|------|--------------|
| (5) | 1 BAS20/635-25 plate-and-frame filter press required |
| (6) | Ion-exchange bed, height = 1. m, diameter = .45 m |
---
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