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Give step-by-step solution with explanation and final answer:3. Spherical dewar for storing liquid oxygen Adewar is a type of specialized vacuum container used to store cryogenic (very low temperature) liquids such as liquid helium, nitrogen, or oxygen. Consider a spherical dewar consisting of an inner metal shell surrounded by a layer of foam insulation that is used to stored liquid oxygen at a temperature Tio. The metal shell has an inner radius ri, an outer radius ro, and a thermal conductivity km. There is a convection coefficient hin between the liquid oxygen and the inner surface of the metal shell. The foam insulation has a thickness tins and a thermal conductivity Kins. There is a convection coefficient hou between the outer surface of the foam insulation and the surrounding air, which is at a temperature T... The outer surface of the foam insulation also has an emissivity € and radiates to the surroundings, which are also at T.. Although the T* scaling means the thermal resistance concept technically does not apply for radiation in the same way it does for conduction and convection, we can nonetheless define an approximate radiation heat transfer coefficient h,,4 [units: W/(m?-K)], which can then be used to define a radiation thermal resistance, analogous to a convection thermal resistance. hq can be approximated as hyqq = 4£0T3,q, where here Ty,y = Tote a) Draw a thermal circuit that describes the heat transfer in this situation. Provide an analytical expression for each resistor in terms of variables given in the problem. b) Provide an analytical expression for the total thermal resistance, Rit, between the liquid oxygen and its surroundings.

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Give step-by-step solution with explanation and final answer:Uploaded Image3. Spherical dewar for storing liquid oxygen Adewar is a type of specialized vacuum container used to store cryogenic (very low temperature) liquids such as liquid helium, nitrogen, or oxygen. Consider a spherical dewar consisting of an inner metal shell surrounded by a layer of foam insulation that is used to stored liquid oxygen at a temperature Tio. The metal shell has an inner radius ri, an outer radius ro, and a thermal conductivity km. There is a convection coefficient hin between the liquid oxygen and the inner surface of the metal shell. The foam insulation has a thickness tins and a thermal conductivity Kins. There is a convection coefficient hou between the outer surface of the foam insulation and the surrounding air, which is at a temperature T... The outer surface of the foam insulation also has an emissivity € and radiates to the surroundings, which are also at T.. Although the T* scaling means the thermal resistance concept technically does not apply for radiation in the same way it does for conduction and convection, we can nonetheless define an approximate radiation heat transfer coefficient h,,4 [units: W/(m?-K)], which can then be used to define a radiation thermal resistance, analogous to a convection thermal resistance. hq can be approximated as hyqq = 4£0T3,q, where here Ty,y = Tote a) Draw a thermal circuit that describes the heat transfer in this situation. Provide an analytical expression for each resistor in terms of variables given in the problem. b) Provide an analytical expression for the total thermal resistance, Rit, between the liquid oxygen and its surroundings.

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Asked by: Rahul
Created at: 2026-01-25 03:05:31

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# 3. Spherical Dewar for Storing Liquid Oxygen — Solution ## (a) Thermal Circuit and Analytical Expressions ### **Thermal Circuit Description** The heat transfer from the liquid oxygen to the surroundings occurs through several steps, each corresponding to a thermal resistance: 1. **Convection from liquid oxygen to inner shell:** Resistance: \( R_{\text{conv,in}} \) 2. **Conduction through metal shell:** Resistance: \( R_{\text{cond,metal}} \) 3. **Conduction through foam insulation:** Resistance: \( R_{\text{cond,ins}} \) 4. **Convection from foam to air:** Resistance: \( R_{\text{conv,out}} \) 5. **Radiation from foam to air:** Resistance: \( R_{\text{rad}} \) **Thermal circuit:** All resistances are in series, except convection and radiation at the outer surface, which are in parallel. #### **Thermal Circuit Diagram (Text Description):** ``` T_lo ----[R_conv,in]----[R_cond,metal]----[R_cond,ins]----*----> T_inf | [R_conv,out] | [R_rad] ``` *At the outer surface, \( R_{\text{conv,out}} \) and \( R_{\text{rad}} \) are in parallel.* --- ### **Analytical Expressions** Let: - \( r_i \): inner radius of metal shell - \( r_ \): outer radius of metal shell (also inner radius of insulation) - \( r_1 \): outer radius of insulation - \( k_m \): thermal conductivity of metal - \( k_{ins} \): thermal conductivity of insulation - \( h_{in} \): convective coefficient (liquid oxygen to inner shell) - \( h_{out} \): convective coefficient (foam to air) - \( h_{rad} \): radiation heat transfer coefficient (foam to air) - \( T_{lo} \): temperature of liquid oxygen - \( T_{\infty} \): temperature of surroundings #### 1. **Convection (liquid to inner shell):** \[ R_{\text{conv,in}} = \frac{1}{4\pi r_i^2 h_{in}} \] #### 2. **Conduction (metal shell, spherical):** \[ R_{\text{cond,metal}} = \frac{1}{4\pi k_m} \cdot \frac{r_ - r_i}{r_i r_} \] Or, more generally (for spherical shells): \[ R_{\text{cond,metal}} = \frac{1}{4\pi k_m} \left( \frac{1}{r_i} - \frac{1}{r_} \right) \] #### 3. **Conduction (foam insulation, spherical):** \[ R_{\text{cond,ins}} = \frac{1}{4\pi k_{ins}} \left( \frac{1}{r_} - \frac{1}{r_1} \right) \] #### 4. **Convection (foam to air):** \[ R_{\text{conv,out}} = \frac{1}{4\pi r_1^2 h_{out}} \] #### 5. **Radiation (foam to air):** \[ R_{\text{rad}} = \frac{1}{4\pi r_1^2 h_{rad}} \] where \( h_{rad} = 4\epsilon \sigma T_{avg}^3 \), and \( T_{avg} = \frac{T_{lo} + T_{\infty}}{2} \). --- ## (b) **Total Thermal Resistance \( R_{tot} \):** At the outer surface, convection and radiation are in parallel, so their *combined resistance* is: \[ \frac{1}{R_{\text{surf}}} = \frac{1}{R_{\text{conv,out}}} + \frac{1}{R_{\text{rad}}} \] \[ R_{\text{surf}} = \left( \frac{1}{R_{\text{conv,out}}} + \frac{1}{R_{\text{rad}}} \right)^{-1} \] ### **Total resistance is then:** \[ R_{tot} = R_{\text{conv,in}} + R_{\text{cond,metal}} + R_{\text{cond,ins}} + R_{\text{surf}} \] --- ### **Summary of the Analytical Expression** \[ \boxed{ R_{tot} = \frac{1}{4\pi r_i^2 h_{in}} + \frac{1}{4\pi k_m} \left( \frac{1}{r_i} - \frac{1}{r_} \right) + \frac{1}{4\pi k_{ins}} \left( \frac{1}{r_} - \frac{1}{r_1} \right) + \left[ \frac{1}{4\pi r_1^2 h_{out}} + \frac{1}{4\pi r_1^2 h_{rad}} \right]^{-1} } \] where - \( h_{rad} = 4 \epsilon \sigma T_{avg}^3 \) - \( T_{avg} = \frac{T_{lo} + T_{\infty}}{2} \) --- ## **Summary Table** | Resistance Type | Expression | |------------------------|-----------------------------------------------------------------------------| | **Convection (in)** | \( R_{\text{conv,in}} = \frac{1}{4\pi r_i^2 h_{in}} \) | | **Conduction (metal)** | \( R_{\text{cond,metal}} = \frac{1}{4\pi k_m}\left(\frac{1}{r_i} - \frac{1}{r_}\right) \) | | **Conduction (ins)** | \( R_{\text{cond,ins}} = \frac{1}{4\pi k_{ins}}\left(\frac{1}{r_} - \frac{1}{r_1}\right) \) | | **Convection (out)** | \( R_{\text{conv,out}} = \frac{1}{4\pi r_1^2 h_{out}} \) | | **Radiation** | \( R_{\text{rad}} = \frac{1}{4\pi r_1^2 h_{rad}} \) | --- **This completes the step-by-step solution.**

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Asked by: Rahul
Created at: 2026-01-25 03:06:09

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# 3. Spherical Dewar for Storing Liquid Oxygen — Solution ## (a) Thermal Circuit and Analytical Expressions ### **Thermal Circuit Description** The heat transfer from the liquid oxygen to the surroundings occurs through several steps, each corresponding to a thermal resistance: 1. **Convection from liquid oxygen to inner shell:** Resistance: \( R_{\text{conv,in}} \) 2. **Conduction through metal shell:** Resistance: \( R_{\text{cond,metal}} \) 3. **Conduction through foam insulation:** Resistance: \( R_{\text{cond,ins}} \) 4. **Convection from foam to air:** Resistance: \( R_{\text{conv,out}} \) 5. **Radiation from foam to air:** Resistance: \( R_{\text{rad}} \) **Thermal circuit:** All resistances are in series, except convection and radiation at the outer surface, which are in parallel. #### **Thermal Circuit Diagram (Text Description):** ``` T_lo ----[R_conv,in]----[R_cond,metal]----[R_cond,ins]----*----> T_inf | [R_conv,out] | [R_rad] ``` *At the outer surface, \( R_{\text{conv,out}} \) and \( R_{\text{rad}} \) are in parallel.* --- ### **Analytical Expressions** Let: - \( r_i \): inner radius of metal shell - \( r_o \): outer radius of metal shell (also inner radius of insulation) - \( r_1 \): outer radius of insulation - \( k_m \): thermal conductivity of metal - \( k_{ins} \): thermal conductivity of insulation - \( h_{in} \): convective coefficient (liquid oxygen to inner shell) - \( h_{out} \): convective coefficient (foam to air) - \( h_{rad} \): radiation heat transfer coefficient (foam to air) - \( T_{lo} \): temperature of liquid oxygen - \( T_{\infty} \): temperature of surroundings #### 1. **Convection (liquid to inner shell):** \[ R_{\text{conv,in}} = \frac{1}{4\pi r_i^2 h_{in}} \] #### 2. **Conduction (metal shell, spherical):** \[ R_{\text{cond,metal}} = \frac{1}{4\pi k_m} \left( \frac{1}{r_i} - \frac{1}{r_o} \right) \] #### 3. **Conduction (foam insulation, spherical):** \[ R_{\text{cond,ins}} = \frac{1}{4\pi k_{ins}} \left( \frac{1}{r_o} - \frac{1}{r_1} \right) \] #### 4. **Convection (foam to air):** \[ R_{\text{conv,out}} = \frac{1}{4\pi r_1^2 h_{out}} \] #### 5. **Radiation (foam to air):** \[ R_{\text{rad}} = \frac{1}{4\pi r_1^2 h_{rad}} \] where \( h_{rad} = 4\epsilon \sigma T_{avg}^3 \), and \( T_{avg} = \frac{T_{lo} + T_{\infty}}{2} \). --- ## (b) **Total Thermal Resistance \( R_{tot} \)** At the outer surface, convection and radiation are in parallel, so their *combined resistance* is: \[ \frac{1}{R_{\text{surf}}} = \frac{1}{R_{\text{conv,out}}} + \frac{1}{R_{\text{rad}}} \] \[ R_{\text{surf}} = \left( \frac{1}{R_{\text{conv,out}}} + \frac{1}{R_{\text{rad}}} \right)^{-1} \] ### **Total resistance is then:** \[ R_{tot} = R_{\text{conv,in}} + R_{\text{cond,metal}} + R_{\text{cond,ins}} + R_{\text{surf}} \] --- ### **Summary of the Analytical Expression** \[ \boxed{ R_{tot} = \frac{1}{4\pi r_i^2 h_{in}} + \frac{1}{4\pi k_m} \left( \frac{1}{r_i} - \frac{1}{r_o} \right) + \frac{1}{4\pi k_{ins}} \left( \frac{1}{r_o} - \frac{1}{r_1} \right) + \left[ \frac{1}{4\pi r_1^2 h_{out}} + \frac{1}{4\pi r_1^2 h_{rad}} \right]^{-1} } \] where - \( h_{rad} = 4 \epsilon \sigma T_{avg}^3 \) - \( T_{avg} = \frac{T_{lo} + T_{\infty}}{2} \) --- ## **Summary Table** | Resistance Type | Expression | |------------------------|-----------------------------------------------------------------------------| | **Convection (in)** | \( R_{\text{conv,in}} = \frac{1}{4\pi r_i^2 h_{in}} \) | | **Conduction (metal)** | \( R_{\text{cond,metal}} = \frac{1}{4\pi k_m}\left(\frac{1}{r_i} - \frac{1}{r_o}\right) \) | | **Conduction (ins)** | \( R_{\text{cond,ins}} = \frac{1}{4\pi k_{ins}}\left(\frac{1}{r_o} - \frac{1}{r_1}\right) \) | | **Convection (out)** | \( R_{\text{conv,out}} = \frac{1}{4\pi r_1^2 h_{out}} \) | | **Radiation** | \( R_{\text{rad}} = \frac{1}{4\pi r_1^2 h_{rad}} \) | --- **This completes the step-by-step solution.**

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