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Give step-by-step solution with explanation and final answer:\cids and bases J E om mo lecule below, and select the statements that apply. If it can Tose Hl draw its co and non-zero formal charges. r Ts HE AS + " Eo N Te fr H, 4 a oo E This molecule will not lose an H' O This molecule will not gain an H' ! fhis molecule could lose an H'. Its, This molecule could gain an H". Its bs ~ conjugate base is: * conjugate acid is: 3 = - gE __- =e ,: > | . | | pe | 4 = | 4 E | SP Rl li i Click and drag Click and drag pr BR cart | to start drawing a drawing a ? structure. structure. 5 Te 3 al RE wl wr a ea |

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Give step-by-step solution with explanation and final answer:Uploaded Image\cids and bases J E om mo lecule below, and select the statements that apply. If it can Tose Hl draw its co and non-zero formal charges. r Ts HE AS + " Eo N Te fr H, 4 a oo E This molecule will not lose an H' O This molecule will not gain an H' ! fhis molecule could lose an H'. Its, This molecule could gain an H". Its bs ~ conjugate base is: * conjugate acid is: 3 = - gE __- =e ,: > | . | | pe | 4 = | 4 E | SP Rl li i Click and drag Click and drag pr BR cart | to start drawing a drawing a ? structure. structure. 5 Te 3 al RE wl wr a ea |

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Asked by: Rahul
Created at: 2026-01-25 20:29:11

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Let's analyze the molecule step by step: ### 1. **Identify the Molecule** The molecule is a **substituted amine** with the structure: ``` | CH3-CH2-CH2-NH2+ | CH3 ``` - The nitrogen has a **positive charge** (NH₂⁺), which means it is already **protonated**. - This means it is the **conjugate acid** form of an amine. --- ### 2. **Can the Molecule Lose H⁺?** - If the molecule were to lose H⁺, it would form a neutral amine (by deprotonating the NH₂⁺ to NH). - **Amines (R-NH₂)** are basic, and their conjugate acids (R-NH₃⁺) can lose a proton to become neutral. - Here, the nitrogen already has three bonds and a positive charge (R-NH₂⁺), so losing a proton would give R-NH. However, in this case, the nitrogen has a methyl substituent and two ethyl groups, so let's rewrite: ``` CH3-CH2-N⁺(CH3)-CH2-CH3 | H2 ``` But from the drawing, it seems to be a simple propylamine with a positive charge (so it's the conjugate acid). --- ### 3. **Can the Molecule Gain H⁺?** - Since the nitrogen is already **protonated** (NH₂⁺), it cannot accept another proton. There is **no lone pair** left for another H⁺. --- ### 4. **Correct Answer** - **This molecule will NOT gain an H⁺** (because it's already fully protonated). - **This molecule COULD lose an H⁺** (because it is the conjugate acid form). --- ### 5. **Draw the Conjugate Base** - Removing one H⁺ from the NH₂⁺ group gives you a neutral amine (NH). #### **Original:** ``` CH3-CH2-CH2-NH2⁺ ``` #### **Conjugate Base:** ``` CH3-CH2-CH2-NH ``` (The nitrogen loses a proton and becomes neutral.) --- ## **Final Answers** **Select:** - [ ] This molecule will not lose an H⁺ - [ ] This molecule will not gain an H⁺ - [x] This molecule could lose an H⁺. Its conjugate base is: (draw structure) - [ ] This molecule could gain an H⁺. Its conjugate acid is: (draw structure) **Conjugate Base Structure:** ``` CH3 | CH3-CH2-NH ``` or, more simply, draw the original molecule, but change NH₂⁺ to NH. --- ### **Summary Table** | Action | Structure after action | |--------------------------------------|-----------------------------| | Lose H⁺ (conjugate base) | CH3-CH2-CH2-NH | | Gain H⁺ (conjugate acid) | **Not possible** | --- **Explanation:** The molecule shown is the conjugate acid of an amine (the nitrogen is already protonated and has a positive charge). It can lose a proton (H⁺) to become a neutral amine, but it cannot gain another proton since there is no lone pair left on nitrogen.

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