VIPSolutions logo ✨ VIPSolutions

Give step-by-step solution with explanation and final answer: Energy conversion: Convert (a) 5 MJ into Btu and (b) 4 barrels of oil into kWh. [ For Joule, M stands for a million, while for Btus, M stands for 1, 000.] 2. Energy usage per person: If the U. S. uses about 100 Quadrillion Btu in one year what is the average energy use per person over the entire year (a) in MMBtu, (b) MJ and (c) MWh (Assume population is 325 million, and 1 quadrillion is a million billion or 1015 Btu). 3. Energy use vs. power: Referring to question 2. What is the average power used per person in Js-1. Explain "in words" what the difference between energy and power is 4. Energy use, lightbulbs and microwaves: Assume average daily (24hr ) energy for a typical home in the US was 83, 835 kJoules a. How many 100W light bulbs could you run flat out for a 24hr period with this power - if these lightbulbs were the only things "on" in the house (You can give me a fractional light - bulb answer or round down) b. If this energy was instead only used to run a 1, 000W microwave after how many hours would the microwave stops? (Hint: it is more than 20hrs and less than 24hrs). c. Show clearly why a home using 84, 000kJ per day every day on average (with actual daily usage varying with Summer and Winter) would use about 8, 500kWh per year.

Question:

Give step-by-step solution with explanation and final answer: Energy conversion: Convert (a) 5 MJ into Btu and (b) 4 barrels of oil into kWh. [ For Joule, M stands for a million, while for Btus, M stands for 1, 000.] 2. Energy usage per person: If the U. S. uses about 100 Quadrillion Btu in one year what is the average energy use per person over the entire year (a) in MMBtu, (b) MJ and (c) MWh (Assume population is 325 million, and 1 quadrillion is a million billion or 1015 Btu). 3. Energy use vs. power: Referring to question 2. What is the average power used per person in Js-1. Explain "in words" what the difference between energy and power is 4. Energy use, lightbulbs and microwaves: Assume average daily (24hr ) energy for a typical home in the US was 83, 835 kJoules a. How many 100W light bulbs could you run flat out for a 24hr period with this power - if these lightbulbs were the only things "on" in the house (You can give me a fractional light - bulb answer or round down) b. If this energy was instead only used to run a 1, 000W microwave after how many hours would the microwave stops? (Hint: it is more than 20hrs and less than 24hrs). c. Show clearly why a home using 84, 000kJ per day every day on average (with actual daily usage varying with Summer and Winter) would use about 8, 500kWh per year.

This is AI generated Response.
Asked by: Om
Created at: 2026-02-02 03:40:41

Final Answer:

Rendered Raw Text
Did you like this answer?
# Step-by-Step Solutions --- ## 1. Energy Conversion ### (a) Convert MJ to Btu **Conversion factor:** - \( 1 \text{ MJ} = 947.817 \text{ Btu} \) **Calculation:** \[ 5 \text{ MJ} \times 947.817 \frac{\text{Btu}}{\text{MJ}} = 4739.09 \text{ Btu} \] **Final Answer:** - **5 MJ = 4,739 Btu** --- ### (b) Convert 4 barrels of oil to kWh **Conversion factors:** - \( 1 \text{ barrel oil} = 5.8 \text{ million Btu} \) - \( 1 \text{ Btu} = .000293071 \text{ kWh} \) **Step 1: Total Btu** \[ 4 \text{ barrels} \times 5.8 \times 10^6 \text{ Btu/barrel} = 23.2 \times 10^6 \text{ Btu} \] **Step 2: Convert to kWh** \[ 23,200,000 \text{ Btu} \times .000293071 \frac{\text{kWh}}{\text{Btu}} = 6,797.25 \text{ kWh} \] **Final Answer:** - **4 barrels of oil = 6,797 kWh** --- ## 2. Energy Usage Per Person in the U.S. Given: - Total U.S. energy use: 100 Quadrillion Btu/year - Population: 325 million - \( 1 \text{ quadrillion} = 10^{15} \) **Total Energy:** \[ 100 \times 10^{15} \text{ Btu} \] **Energy per person:** \[ \frac{100 \times 10^{15} \text{ Btu}}{325 \times 10^6 \text{ people}} = 307,692,308 \text{ Btu/person/year} \] ### (a) In MMBtu - \( 1 \text{ MMBtu} = 1,000,000 \text{ Btu} \) \[ \frac{307,692,308 \text{ Btu}}{1,000,000} = 307.7 \text{ MMBtu/person/year} \] ### (b) In MJ - \( 1 \text{ Btu} = 1.05506 \text{ kJ} \) - \( 1 \text{ MJ} = 1,000 \text{ kJ} \) \[ 307,692,308 \text{ Btu} \times 1.05506 = 324,234,204 \text{ kJ} \] \[ \frac{324,234,204}{1,000} = 324,234 \text{ MJ/person/year} \] ### (c) In MWh - \( 1 \text{ Btu} = .000293071 \text{ kWh} \) - \( 1 \text{ MWh} = 1,000 \text{ kWh} \) \[ 307,692,308 \text{ Btu} \times .000293071 = 90,231 \text{ kWh} \] \[ \frac{90,231}{1,000} = 90.2 \text{ MWh/person/year} \] --- **Final Answers:** - (a) **307.7 MMBtu/person/year** - (b) **324,234 MJ/person/year** - (c) **90.2 MWh/person/year** --- ## 3. Energy Use vs. Power ### Average Power Used per Person (in J/s) **Step 1: Find MJ/year per person from above:** \( 324,234,204 \text{ kJ} = 324,234,204,000 \text{ J} \) **Step 2: Number of seconds in a year:** \( 365 \times 24 \times 360 = 31,536,000 \) s **Step 3: Power (J/s):** \[ \frac{324,234,204,000 \text{ J}}{31,536,000 \text{ s}} = 10,288 \text{ J/s} \] **Final Answer:** - **Average power = 10,288 J/s (W) per person** ### Explanation: Energy vs. Power - **Energy** is the total amount of work done or heat transferred (measured in Joules, kWh, etc.). - **Power** is the *rate* at which energy is used or transferred (measured in Watts, or J/s). **In words:** Energy tells you how much you have used in total, while power tells you how fast you are using it at any instant. --- ## 4. Energy Use, Lightbulbs and Microwaves Given: - Home uses 83,835 kJ per day ### (a) 100 W Lightbulbs **Step 1: Convert kJ to kWh** \[ 83,835 \text{ kJ} \div 3,600 = 23.29 \text{ kWh/day} \] **Step 2: Energy used by one 100 W bulb in 24 hours** \[ 100 \text{ W} \times 24 \text{ h} = 2,400 \text{ Wh} = 2.4 \text{ kWh} \] **Step 3: Number of bulbs** \[ \frac{23.29 \text{ kWh}}{2.4 \text{ kWh/bulb}} = 9.70 \] **Final Answer:** - **You could run 9 full 100 W lightbulbs for 24 hours.** --- ### (b) 1,000 W Microwave **Step 1: How many hours will 23.29 kWh run a 1,000 W (1 kW) microwave?** \[ \frac{23.29 \text{ kWh}}{1 \text{ kW}} = 23.29 \text{ hours} \] **Final Answer:** - **The microwave would run for 23.29 hours.** --- ### (c) Annual Usage: 84,000 kJ/day to kWh/year **Step 1: Daily kWh** \[ 84,000 \text{ kJ} \div 3,600 = 23.33 \text{ kWh/day} \] **Step 2: Annual kWh** \[ 23.33 \text{ kWh/day} \times 365 = 8,515 \text{ kWh/year} \] **Explanation:** - Each day, the house uses about 23.33 kWh. - Over a year, this totals about 8,515 kWh, close to the stated value of 8,500 kWh/year. --- ## Summary Table | Conversion/Calculation | Value/Result | |------------------------------------------|-----------------------| | 5 MJ to Btu | 4,739 Btu | | 4 barrels oil to kWh | 6,797 kWh | | Per person, per year: | | | ... in MMBtu | 307.7 MMBtu | | ... in MJ | 324,234 MJ | | ... in MWh | 90.2 MWh | | Average power (J/s) per person | 10,288 J/s (W) | | 100 W bulbs, 24h, 83,835 kJ/day | 9 bulbs | | 1,000 W microwave, hours on 83,835 kJ | 23.29 hours | | 84,000 kJ/day to kWh/year | 8,515 kWh/year | --- **Note:** - For Btu, M = 1,000 (not million); for Joules, M = 1,000,000. - Use appropriate conversion factors for precise answers. - Always check units during conversions.

📢 Instructions:

  • Ask anything relatd to above question only.
  • For new Question goto :

Study Help, Fast Answers

VIPSolutions focuses on clear, step‑by‑step explanations so you can learn quickly. Whether you need an AI‑generated walkthrough or a short hint to get unstuck, each solution is organized for fast reading and easy review later.

Search similar questions, compare approaches, and bookmark the best answers for revision. Our goal is simple: quick, reliable study help that feels natural—not noisy.