Give step-by-step solution with explanation and final answer:
(20 pts) What role could benzylchloroformate have in the synthesis of a dipeptide? Provide an example using any two amino acids, DCC and HOBt as coupling reagents, and any other reagents as needed. Draw a reasonable step-by-step mechanism for the entire process, from individual amino acids to the final dipeptide.
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Give step-by-step solution with explanation and final answer:
(20 pts) What role could benzylchloroformate have in the synthesis of a dipeptide? Provide an example using any two amino acids, DCC and HOBt as coupling reagents, and any other reagents as needed. Draw a reasonable step-by-step mechanism for the entire process, from individual amino acids to the final dipeptide.
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Asked by: Rahul
Created at: 2026-02-05 07:53:08
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# Role of Benzylchloroformate in Dipeptide Synthesis
## Benzylchloroformate (Cbz-Cl) in Peptide Synthesis
**Benzylchloroformate** (Cbz-Cl) is primarily used to protect the **amino group** of amino acids during peptide synthesis. The **Cbz group** (also called **Z group**) prevents unwanted side reactions by blocking the amine, and can be removed (deprotected) later by hydrogenolysis.
---
## Example: Synthesis of Gly-Phe (Glycylphenylalanine) Dipeptide
### **Goal:**
Synthesize Gly-Phe from glycine (Gly) and phenylalanine (Phe) using DCC/HOBt for coupling and Cbz-Cl for protection.
---
## Step 1: Protect the Amino Group of Glycine
**Reagents:** Glycine, Cbz-Cl, NaHCO₃ (aqueous)
**Reaction:**
\[
\ce{H2N-CH2-COOH + C6H5CH2OCOCl ->[NaHCO3] C6H5CH2OCO-NH-CH2-COOH + HCl}
\]
**Mechanism:**
1. Nucleophilic attack of glycine's amine on Cbz-Cl.
2. Formation of Cbz-protected glycine (**Cbz-Gly**).
**Result:**

*Cbz-protected glycine structure (Cbz-Gly-OH)*
---
## Step 2: Activate the Carboxyl Group of Cbz-Gly
**Reagents:**
- Cbz-Gly-OH
- DCC (N,N'-dicyclohexylcarbodiimide)
- HOBt (1-hydroxybenzotriazole)
- Phe-OH (phenylalanine, unprotected)
**Mechanism:**
1. DCC reacts with the carboxyl group of Cbz-Gly, forming an **O-acylurea** intermediate.
2. HOBt displaces DCC, forming a more reactive **OBt ester**.
3. The amino group of Phe attacks the OBt ester, forming the peptide bond.
4. Dicyclohexylurea (DCU) precipitates out.
**Stepwise:**
1. Cbz-Gly-OH + DCC → Cbz-Gly-O-DCC (O-acylisourea intermediate)
2. Cbz-Gly-O-DCC + HOBt → Cbz-Gly-OBt (active ester) + DCU
3. Cbz-Gly-OBt + H₂N-Phe-OH → Cbz-Gly-Phe-OH + HOBt
**Result:**

*Peptide bond formation via DCC/HOBt coupling*
---
## Step 3: Deprotect the Cbz Group
**Reagents:**
- Cbz-Gly-Phe
- H₂ (hydrogen gas), Pd/C (palladium on carbon)
**Mechanism:**
- Catalytic hydrogenolysis removes the Cbz group, regenerating the free N-terminus.
\[
\ce{Cbz-Gly-Phe + H2 ->[Pd/C] H2N-Gly-Phe + C6H5CH3}
\]
**Result:**
- Final dipeptide: **Gly-Phe (H₂N-Gly-Phe-OH)**
---
## **Summary of Steps**
1. **Protection:** Block Gly's amine with Cbz-Cl → **Cbz-Gly-OH**
2. **Activation & Coupling:**
- Activate Cbz-Gly's carboxyl group with DCC/HOBt.
- Add Phe; peptide bond forms → **Cbz-Gly-Phe**
3. **Deprotection:** Remove Cbz group via hydrogenolysis → **Gly-Phe**
---
## **Full Mechanism Overview**
1. **Cbz protection of Glycine:**
- Amine attacks Cbz-Cl → **Cbz-Gly-OH**
2. **DCC/HOBt Activation and Coupling:**
- Carboxyl O attacks DCC → O-acylurea intermediate
- HOBt attacks, displacing DCC → OBt ester
- Amine of Phe attacks OBt ester → peptide bond
3. **Cbz Deprotection:**
- H₂/Pd-C removes Cbz group → free dipeptide
---
## **Final Answer (with Mechanism and Explanation)**
**Benzylchloroformate (Cbz-Cl) is used to protect the amino group of an amino acid (e.g., glycine) during peptide synthesis, preventing unwanted side reactions. The protected amino acid is then coupled with another amino acid (e.g., phenylalanine) using DCC/HOBt. After coupling, the Cbz protecting group is removed by hydrogenolysis to yield the free dipeptide.**
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