Let's solve each reaction step-by-step, identifying the reaction type and providing the final product. --- ## a) **Given:** - Reactant:  (ethyl acetoacetate) - Reagent: \( \mathrm{Br_2, NaOEt} \) - Product: ? **Type:** α-Bromination ### **Step-by-step:** 1. **NaOEt** deprotonates the α-hydrogen (adjacent to the carbonyl), forming an enolate. 2. **Br₂** reacts with the enolate, brominating the α-position. **Final answer:** - Product:  - Structure:  - Type: α-Bromination --- ## b) **Given:** - Reactant: Carboxylic acid - Reagent: SOCl₂ - Product: ? **Type:** Formation of an acid chloride ### **Step-by-step:** 1. **SOCl₂** converts carboxylic acid to acid chloride. **Final answer:** - Product: Acid chloride (replace OH with Cl) - Type: Formation of an acid chloride --- ## c) **Given:** - Reactant: Acid chloride - Reagent: Amine (with aromatic ring) - Product: ? **Type:** Formation of an amide ### **Step-by-step:** 1. **Aromatic amine** attacks the acid chloride, forming an amide. **Final answer:** - Product: Amide (replace Cl with NHR, where R is the aromatic group) - Type: Formation of an amide --- ## d) **Given:** - Reactant: Cyclohexanone - Reagents: 1. LDA, THF 2. Benzyl bromide **Type:** Alkylation of Enolate ### **Step-by-step:** 1. **LDA** forms an enolate at the α-position. 2. The enolate attacks benzyl bromide, alkylating the α-carbon. **Final answer:** - Product: Cyclohexanone with a benzyl group at the α-position. - Type: α-Alkylation --- ## e) **Given:** - Reactant: Alcohol + Carboxylic acid - Reagent: Acid - Product: Ester **Type:** Fischer Esterification ### **Step-by-step:** 1. Alcohol reacts with carboxylic acid under acidic conditions to form ester. **Final answer:** - Product: Ester (combine alcohol and acid) - Type: Fischer Esterification --- ## f) **Given:** - Reactant: Malonic ester - Reagents: 1. EtO⁻, RX 2. H₃O⁺, heat **Type:** Malonic Ester Synthesis ### **Step-by-step:** 1. Deprotonation, alkylation, hydrolysis, and decarboxylation yield substituted acetic acid. **Final answer:** - Product: Substituted acetic acid - Type: Malonic Ester Synthesis --- ## g) **Given:** - Reactant: Ester with an α-proton - Reagents: 1. EtO⁻, Ester 2. H₃O⁺ **Type:** Claisen Condensation ### **Step-by-step:** 1. Enolate attacks another ester, forming β-ketoester. **Final answer:** - Product: β-Ketoester - Type: Claisen Condensation --- ## h) **Given:** - Reactant: - Reagents: 1. MeO⁻, OMe 2. H₃O⁺, heat **Type:** Dieckmann Condensation (intramolecular Claisen) ### **Step-by-step:** 1. Intramolecular condensation forms cyclic β-ketoester. **Final answer:** - Product: Cyclic β-ketoester - Type: Dieckmann Condensation --- ## i) **Given:** - Reactant: - Reagents: 1. H₂O, THF **Type:** Aldol Addition ### **Step-by-step:** 1. Enolate addition to aldehyde/ketone forms β-hydroxy carbonyl. **Final answer:** - Product: β-Hydroxy carbonyl - Type: Aldol Addition --- ## j) **Given:** - Reactant: - Reagents: 1. PhCHO, NaOH, EtOH **Type:** Aldol Condensation ### **Step-by-step:** 1. Enolate addition, followed by dehydration to α,β-unsaturated carbonyl. **Final answer:** - Product: α,β-Unsaturated carbonyl (enone or enal) - Type: Aldol Condensation --- ### **Summary Table** | Letter | Product (structure) | Type | |--------|---------------------------------|------------------------------| | a | α-Bromoacetoacetate | α-Bromination | | b | Acid chloride | Formation of acid chloride | | c | Amide | Formation of an amide | | d | α-Benzyl cyclohexanone | α-Alkylation | | e | Ester | Fischer Esterification | | f | Substituted acetic acid | Malonic Ester Synthesis | | g | β-Ketoester | Claisen Condensation | | h | Cyclic β-ketoester | Dieckmann Condensation | | i | β-Hydroxy carbonyl | Aldol Addition | | j | α,β-Unsaturated carbonyl | Aldol Condensation | If you need structures drawn out, let me know!