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Question:
Give step-by-step solution with explanation and final answer:Problam:2: Assume ile DOF motion control system whose mathematical mode given a5.
8600) +90) 41 = KT
Friis system, the ore conta nd he nel con spc be gn 1 (0) = 2+ 823d
5 5, 1 To pte oh wid fore od spl, Furor, i 0 tht the
troche Stes compensa and he em ly grand othe ort
inl hs est.
1 the coionment 1 fis enorme fo which th cori fr con bo gm 35
RCO) = (1 snd th tr 5 pd 10 et Sree crit force
prod
Woke con th chin efor i
2) pene 5 Beil eqoen fo he are ten bt 1) hor ston rss
piscatponpmpsiormadiafofita ig
Pr at tea ERR Te —
pilronsbirieny
in th rr dries 2) we dr the xprsson oh dosed cles fo
eral £0)
11th rman has fore L. on)bor wch th otc fe co bo ph a F) =
Kan) 1 DA) md th ye + pened rch crn os bens F7(1) hrm
i Wnt nthe cking re for ts pte.
3) pons» ier waa oe the arr gen i ut 1) whos schon rss bn
Errata dog arm ay lve.
57 We de Sun for th Gantt ston gh I pr 2 ig 0
aah te dics 2, re eds cron Vrain of FV)
This is AI generated Response.
Asked by: gvr
Created at: 2025-06-17 16:03:02
Final Answer:
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Let's break down **Problem 2** step by step:
---
## **Given:**
A single-DOF motion control system with the model:
\[
a(q) \ddot{q}(t) + b(q, \dot{q}) + g(q) + \tau_{ext} = k_c f_e^*(t)
\]
where:
- \( a(q) \): inertia (can be \( a_0 + \Delta a \))
- \( b(q, \dot{q}) \): damping/friction
- \( g(q) \): gravity
- \( \tau_{ext} \): external disturbance (compensated)
- \( k_c \): torque constant
- \( f_e^*(t) \): force at environment
Assume disturbance is compensated and initial system is at the contact point.
---
## **a) Lossless environment (contact force: \( f_e(q) = k_e(q - q_e^*) \))**
### **1) Write down the tracking error for this system.**
Let the desired force profile be \( f_e^*(t) \), and the corresponding desired position be \( q_e^*(t) \).
**Tracking error:**
\[
e(t) = q(t) - q_e^*(t)
\]
---
### **2) Propose a differential equation for the error whose solution decays to zero.**
From \( f_e(q) = k_e(q - q_e^*) \), we want \( f_e(q) \to f_e^*(t) \), so:
\[
k_e(q - q_e^*) = f_e^*(t) \implies q_e^*(t) = q - \frac{f_e^*(t)}{k_e}
\]
But for tracking, define \( e(t) = q(t) - q_e^*(t) \).
**System dynamics:**
\[
a(q) \ddot{q} + b(q, \dot{q}) + g(q) = k_c f_e^*(t)
\]
Assume compensation and at equilibrium, \( a(q) \ddot{q} = 0 \), \( b(q, \dot{q}) = 0 \), \( g(q) = 0 \):
\[
0 = k_c f_e^*(t)
\]
For control, let's linearize and use PD control:
\[
a_0 \ddot{q} + k_e(q - q_e^*) = f_e^*(t)
\]
So,
\[
a_0 \ddot{q} + k_e e(t) = f_e^*(t)
\]
Let \( f_e^*(t) \) be the reference; set \( a_0 \ddot{e}(t) + k_e e(t) = 0 \):
\[
\ddot{e}(t) + \frac{k_e}{a_0} e(t) = 0
\]
---
### **3) Condition for convergence without oscillations:**
The characteristic equation is:
\[
s^2 + \frac{k_e}{a_0} = 0
\implies s = \pm j\sqrt{\frac{k_e}{a_0}}
\]
This is purely imaginary (undamped), so the system will oscillate unless damping is added.
To avoid oscillation (i.e. critically damped or overdamped), add a damping term \( b \dot{e}(t) \):
\[
a_0 \ddot{e}(t) + b \dot{e}(t) + k_e e(t) = 0
\]
Characteristic equation:
\[
s^2 + \frac{b}{a_0}s + \frac{k_e}{a_0} = 0
\]
For non-oscillatory convergence:
\[
\left(\frac{b}{a_0}\right)^2 > 4\frac{k_e}{a_0} \implies b^2 > 4k_e a_0
\]
---
### **4) Desired acceleration expression for tracking \( f_e^*(t) \):**
From earlier:
\[
a_0 \ddot{q}(t) + k_e (q(t) - q_e^*(t)) = f_e^*(t)
\]
We want \( q(t) \) to track \( q_e^*(t) \) so set:
\[
a_0 \ddot{q}(t) = f_e^*(t) - k_e (q(t) - q_e^*(t))
\]
Or,
\[
\ddot{q}(t) = \frac{1}{a_0} \left[ f_e^*(t) - k_e (q(t) - q_e^*(t)) \right]
\]
---
## **b) If the environment has losses (i.e., friction: \( f_e(q, \dot{q}) = k_e(q - q_e^*) + b_e \dot{q} \)):**
### **1) Write down the tracking error:**
Same as before:
\[
e(t) = q(t) - q_e^*(t)
\]
---
### **2) Propose a differential equation for the error:**
System equation:
\[
a_0 \ddot{q} + b_e \dot{q} + k_e(q - q_e^*) = f_e^*(t)
\]
Tracking error:
\[
a_0 \ddot{e}(t) + b_e \dot{e}(t) + k_e e(t) = 0
\]
---
### **3) Condition for fast, non-oscillatory convergence:**
Characteristic equation:
\[
s^2 + \frac{b_e}{a_0} s + \frac{k_e}{a_0} = 0
\]
For critically damped or overdamped (no oscillations):
\[
\left(\frac{b_e}{a_0}\right)^2 \geq 4\frac{k_e}{a_0}
\implies b_e^2 \geq 4 k_e a_0
\]
---
### **4) Desired acceleration for tracking \( f_e^*(t) \):**
From above:
\[
a_0 \ddot{q}(t) + b_e \dot{q}(t) + k_e (q(t) - q_e^*(t)) = f_e^*(t)
\]
So,
\[
\ddot{q}(t) = \frac{1}{a_0} \left[ f_e^*(t) - b_e \dot{q}(t) - k_e (q(t) - q_e^*(t)) \right]
\]
---
## **Summary Table**
| Part | Tracking Error | Error Dynamics | Non-oscillation Condition | Desired Acceleration |
|------|---------------|---------------|--------------------------|---------------------|
| a) | \( q - q_e^* \) | \( \ddot{e} + \frac{k_e}{a_0}e = 0 \) | Add damping: \( b^2 > 4k_e a_0 \) | \( \ddot{q} = \frac{1}{a_0} [f_e^* - k_e (q-q_e^*)] \) |
| b) | \( q - q_e^* \) | \( \ddot{e} + \frac{b_e}{a_0}\dot{e} + \frac{k_e}{a_0}e = 0 \) | \( b_e^2 \geq 4k_e a_0 \) | \( \ddot{q} = \frac{1}{a_0} [f_e^* - b_e \dot{q} - k_e(q-q_e^*)] \) |
---
If you need the derivation for any step or a more detailed explanation, **let me know**!
Question:
i need only final Answers of both parts
This is AI generated Response.
Asked by: gvr
Created at: 2025-06-17 16:25:59
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