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Give step-by-step solution with explanation and final answer:Given two matrices A and Blt C be the product C = AB (ar we sum the Gimeno of 4 nd Bar such hat the ulplcan fs dated) The produ AB canbe computed in two dfernt vars. © 1 Molphcaon fy cots: Lot, an. b the cok of the tices and especively By dafiton of matic rmarix ulplcation. weve y= Ab. 43ch cola fhe matt Cs gen b th proc fhe me Als 1h corespandng cola of he mat 8: 48 = [Ab Ab, Ab 2 Molipkation by ows: Lets, and and be he 4h rows ofthe maces A and C respacively By definton of mat marx mupicaten; we have. 5.6) 2.1 ssc row of mas fs given by psu of coreponding ow of Ams heise 8. A= | #18) + in 5 {ns exerci we wR els th wo methods of computing th product Twa 3 3 random tices wih envi between and 10 ar generated fo you sing the commands: R etbrcand(3), Sei0%rand(3) Th command rand(3) genesis random 3 = 3 mts with ris Beane 0 41,1 Wo ily hl mat by 100 tht a ans betwen 0 3nd 10 1 Woipicaton by columns Uke he-opertr esac est, socond snd id com of th tc ad lor hm th aries

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Give step-by-step solution with explanation and final answer:Uploaded ImageGiven two matrices A and Blt C be the product C = AB (ar we sum the Gimeno of 4 nd Bar such hat the ulplcan fs dated) The produ AB canbe computed in two dfernt vars. © 1 Molphcaon fy cots: Lot, an. b the cok of the tices and especively By dafiton of matic rmarix ulplcation. weve y= Ab. 43ch cola fhe matt Cs gen b th proc fhe me Als 1h corespandng cola of he mat 8: 48 = [Ab Ab, Ab 2 Molipkation by ows: Lets, and and be he 4h rows ofthe maces A and C respacively By definton of mat marx mupicaten; we have. 5.6) 2.1 ssc row of mas fs given by psu of coreponding ow of Ams heise 8. A= | #18) + in 5 {ns exerci we wR els th wo methods of computing th product Twa 3 3 random tices wih envi between and 10 ar generated fo you sing the commands: R etbrcand(3), Sei0%rand(3) Th command rand(3) genesis random 3 = 3 mts with ris Beane 0 41,1 Wo ily hl mat by 100 tht a ans betwen 0 3nd 10 1 Woipicaton by columns Uke he-opertr esac est, socond snd id com of th tc ad lor hm th aries

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Asked by: gvr
Created at: 2025-06-18 04:05:42

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Let's break down the step-by-step solution as described in your instructions: --- ### **Step 1: Generate Two 3x3 Random Matrices** Commands: ```matlab R = 10*rand(3); S = 10*rand(3); ``` - `rand(3)` creates a 3x3 matrix with entries between 0 and 1. - Multiplying by 10 gives entries between 0 and 10. --- ### **Step 2: Multiplication by Columns** Let’s denote: - \( R \) as matrix \( A \) - \( S \) as matrix \( B \) #### **Extract Columns of S:** ```matlab s1 = S(:,1); % First column s2 = S(:,2); % Second column s3 = S(:,3); % Third column ``` #### **Compute Each Column of C:** - \( c_1 = R \times s_1 \) - \( c_2 = R \times s_2 \) - \( c_3 = R \times s_3 \) ```matlab c1 = R * s1; c2 = R * s2; c3 = R * s3; ``` #### **Build Matrix C by Columns:** ```matlab C = [c1 c2 c3]; ``` --- ### **Step 3: Multiplication by Rows** #### **Extract Rows of R:** ```matlab r1 = R(1,:); % First row r2 = R(2,:); % Second row r3 = R(3,:); % Third row ``` #### **Compute Each Row of Q:** - \( q_1 = r_1 \times S \) - \( q_2 = r_2 \times S \) - \( q_3 = r_3 \times S \) ```matlab q1 = r1 * S; q2 = r2 * S; q3 = r3 * S; ``` #### **Build Matrix Q by Rows:** ```matlab Q = [q1; q2; q3]; ``` --- ### **Step 4: Compare the Results** Both methods should yield the same result: ```matlab disp(C) disp(Q) ``` You can also use: ```matlab isequal(C, Q) ``` This will return `1` (true) if the matrices are identical. --- ### **Final Answer** The product matrix \( C = Q = R \times S \) can be computed either by: - Multiplying by columns (building up each column by multiplying \( R \) by each column of \( S \)), **OR** - Multiplying by rows (building up each row by multiplying each row of \( R \) by \( S \)). **Both methods will give the same matrix product.** --- **Summary Table for MATLAB Steps:** | Step | Command | Description | |------|-------------|-------------------------------------------| | 1 | R=10*rand(3); S=10*rand(3); | Generate random matrices | | 2 | s1=S(:,1); s2=S(:,2); s3=S(:,3); | Extract columns of S | | | c1=R*s1; c2=R*s2; c3=R*s3; | Multiply by columns | | | C=[c1 c2 c3]; | Build matrix by columns | | 3 | r1=R(1,:); r2=R(2,:); r3=R(3,:); | Extract rows of R | | | q1=r1*S; q2=r2*S; q3=r3*S; | Multiply by rows | | | Q=[q1; q2; q3]; | Build matrix by rows | | 4 | isequal(C,Q) | Compare results | --- **You have now learned two equivalent methods to compute matrix multiplication: by columns and by rows!**

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