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Give step-by-step solution with explanation and final answer:4.1 Evaluate the following MATLAB expressions. (@5 >= 5.5 (b) 34 < 34 (ec) xor (FIFR=EDINC ELS pil false (€) ~~(35 / 17) == (35 / 17) fH) (7

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Give step-by-step solution with explanation and final answer:Uploaded Image4.1 Evaluate the following MATLAB expressions. (@5 >= 5.5 (b) 34 < 34 (ec) xor (FIFR=EDINC ELS pil false (€) ~~(35 / 17) == (35 / 17) fH) (7

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Asked by: gvr
Created at: 2025-08-02 14:56:29

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Let's solve each MATLAB expression step by step: --- ### (a) \( 5 \geq 5.5 \) - \( 5 \geq 5.5 \) evaluates if 5 is **greater than or equal to** 5.5. - \( 5 \) is **not** greater than or equal to \( 5.5 \). **Answer:** `false` or `0` --- ### (b) \( 34 < 34 \) - \( 34 < 34 \) checks if 34 is **less than** 34. - This is **false** because 34 is **equal** to 34, not less. **Answer:** `false` or `0` --- ### (c) `xor(17 - pi < 15, pi < 3)` Evaluate inside first: - \( \pi \approx 3.1416 \) - \( 17 - \pi \approx 13.8584 \) - \( 13.8584 < 15 \) is **true**. - \( \pi < 3 \) is **false**. `xor(true, false)` is **true** (since only one is true). **Answer:** `true` or `1` --- ### (d) `true > false` - In MATLAB, `true` is `1` and `false` is `0`. - \( 1 > 0 \) is **true**. **Answer:** `true` or `1` --- ### (e) `~(35 / 17) == (35 / 17)` - \( 35 / 17 \approx 2.0588 \) - `~(35/17)` in MATLAB: `~` is the logical NOT, applied to nonzero values gives `false` (`0`). - So, `~(35 / 17)` is `false` or `0`. - `0 == 2.0588` is **false**. **Answer:** `false` or `0` --- ### (f) `(7 <= 8) == (3 / 2 == 1)` - \( 7 \leq 8 \) is **true** (`1`). - \( 3 / 2 = 1.5 \), so \( 1.5 == 1 \) is **false** (`0`). - \( 1 == 0 \) is **false**. **Answer:** `false` or `0` --- ### (g) \( 17.5 \ \&\&\ (3.3 > 2.) \) - \( 3.3 > 2.0 \) is **true** (`1`). - In MATLAB, logical AND (`&&`) requires both sides to be logically true (nonzero). - \( 17.5 \) is nonzero, so **true**. - `true && true` is **true**. **Answer:** `true` or `1` --- ## **Summary Table** | Part | Expression | Answer (MATLAB) | |------|-----------------------------------------------|-----------------| | (a) | 5 >= 5.5 | 0 (false) | | (b) | 34 < 34 | 0 (false) | | (c) | xor(17 - pi < 15, pi < 3) | 1 (true) | | (d) | true > false | 1 (true) | | (e) | ~(35 / 17) == (35 / 17) | 0 (false) | | (f) | (7 <= 8) == (3 / 2 == 1) | 0 (false) | | (g) | 17.5 && (3.3 > 2.) | 1 (true) |

Question:

i need step by step detailed explanation and calculations of each part along with the final answer without table

This is AI generated Response.
Asked by: gvr
Created at: 2025-08-02 14:58:40

Final Answer:

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Let's evaluate each MATLAB expression step-by-step with detailed explanations: --- **Part (a):** `5 >= 5.5` - The `>=` operator checks if the left operand is **greater than or equal to** the right operand. - Here, compare 5 and 5.5: - 5 is **less** than 5.5. - Therefore, **5 >= 5.5** evaluates to **false**. - In MATLAB, `false` is represented as `0`. **Final answer:** `0` --- **Part (b):** `34 < 34` - The `<` operator checks if the left operand is **less than** the right operand. - Here, compare 34 and 34: - 34 is **equal** to 34, not less. - So, **34 < 34** evaluates to **false**. - In MATLAB, this is `0`. **Final answer:** `0` --- **Part (c):** `xor(17 - pi < 15, pi < 3)` - First, evaluate each logical condition: - `17 - pi < 15` - \( \pi \approx 3.1416 \), - \( 17 - 3.1416 \approx 13.8584 \), - Is 13.8584 < 15? Yes, **true**. - `pi < 3` - Is 3.1416 < 3? No, **false**. - Now, `xor(true, false)`: - `xor` returns **true** if exactly one argument is true. - Since one is true and the other false, the result is **true**. - In MATLAB, `true` is represented as `1`. **Final answer:** `1` --- **Part (d):** `true > false` - In MATLAB: - `true` = `1`, - `false` = `0`. - Evaluate `1 > 0`: Is 1 greater than 0? Yes. - Therefore, the expression evaluates to **true**. - MATLAB's `true` is `1`. **Final answer:** `1` --- **Part (e):** `~(35 / 17) == (35 / 17)` - Calculate `35 / 17`: - \( 35 / 17 \approx 2.0588 \). - Apply the logical NOT operator `~`: - In MATLAB, `~` applied to a nonzero number treats it as logical true (1), so: - `~(2.0588)` converts 2.0588 to logical true (`1`), then negates it: - `~(nonzero)` yields **false** (`0`). - So, `~(35 / 17)` results in `0`. - Now compare: - `0 == 2.0588`: - Is 0 equal to 2.0588? No, **false**. - MATLAB's boolean `false` is `0`. **Final answer:** `0` --- **Part (f):** `(7 <= 8) == (3 / 2 == 1)` - Evaluate `(7 <= 8)`: - 7 less than or equal to 8? Yes, **true** (`1`). - Evaluate `(3 / 2 == 1)`: - \( 3 / 2 = 1.5 \), - Is 1.5 equal to 1? No, **false** (`0`). - Now, compare the two results: - `1 == 0`? No, **false**. - MATLAB's `false` is `0`. **Final answer:** `0` --- **Part (g):** `17.5 && (3.3 > 2.)` - First, evaluate `(3.3 > 2.)`: - Is 3.3 greater than 2? Yes, **true** (`1`). - The logical AND operator `&&` in MATLAB: - Requires both operands to be true. - The first operand is `17.5`: - In MATLAB, any non-zero number is considered **true**. - The second operand is `1` (true). - Therefore: - `true && true` yields **true** (`1`). **Final answer:** `1` --- **Summary of all parts:** - **(a):** 0 - **(b):** 0 - **(c):** 1 - **(d):** 1 - **(e):** 0 - **(f):** 0 - **(g):** 1 This completes the step-by-step evaluation with detailed explanations.

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