Give step-by-step solution with explanation and final answer:We wish to produce a 0.3-in.-thick plate of 3105 aluminum having a tensile strength
of at least 25.000 psi and a %elongation of at least 5%. The original thickness of the
plate is 3 in. The maximum cold work in each step is 80%. Describe the cold work-
ing and annealing steps required to make this product. Compare this process with
that you would recommend if you could do the initial deformation by hot working.
Question:
Give step-by-step solution with explanation and final answer:We wish to produce a 0.3-in.-thick plate of 3105 aluminum having a tensile strength
of at least 25.000 psi and a %elongation of at least 5%. The original thickness of the
plate is 3 in. The maximum cold work in each step is 80%. Describe the cold work-
ing and annealing steps required to make this product. Compare this process with
that you would recommend if you could do the initial deformation by hot working.
This is AI generated Response.
Asked by: manish kumar
Created at: 2025-08-16 09:17:17
Final Answer:
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Let's break down the solution step by step:
---
### **Step 1: Understanding the Problem**
- **Material:** 3105 Aluminum
- **Initial thickness (\( t_0 \))**: 3.0 in
- **Final thickness (\( t_f \))**: 0.3 in
- **Tensile strength required:** ≥ 25,000 psi
- **% Elongation required:** ≥ 5%
- **Maximum cold work per step:** 80% reduction in thickness
---
### **Step 2: Calculate Total % Reduction Required**
\[
\text{Total % Reduction} = \frac{t_0 - t_f}{t_0} \times 100\%
\]
\[
= \frac{3.0 - 0.3}{3.0} \times 100\% = \frac{2.7}{3.0} \times 100\% = 90\%
\]
---
### **Step 3: Maximum Cold Work per Step**
Maximum reduction per cold working step = 80%.
Let’s check if we can do this in one step:
- After one 80% reduction:
\[
t = t_0 \times (1 - 0.8) = 3.0 \times 0.2 = 0.6 \text{ in}
\]
- But we need 0.3 in, so **one step isn't enough**.
#### **Number of Steps Needed**
Let’s denote the thickness after the first step as \( t_1 \):
1. **First Step:**
\[
t_1 = t_0 \times (1 - 0.8) = 3.0 \times 0.2 = 0.6 \text{ in}
\]
2. **Second Step:**
\[
t_2 = t_1 \times (1 - 0.8) = 0.6 \times 0.2 = 0.12 \text{ in}
\]
This is less than 0.3 in, so we cannot do two full 80% reductions.
#### **Better Approach: Two Steps, Second with Less Reduction**
- **Step 1:** 80% reduction: \( 3.0 \to 0.6 \) in
- **Step 2:** Reduction from 0.6 in to 0.3 in:
\[
\text{Reduction} = \frac{0.6 - 0.3}{0.6} \times 100\% = 50\%
\]
Which is less than 80%, so **feasible**.
---
### **Step 4: Cold-Working and Annealing Procedure**
- **Step 1:** Cold work from 3.0 in to 0.6 in (80% reduction)
- Likely, after this much cold work, the material will be heavily strain hardened and brittle, with low ductility.
- **Anneal** after this step to restore ductility.
- **Step 2:** Cold work from 0.6 in to 0.3 in (50% reduction)
- After this, the material will again be strain hardened.
- For the required properties (tensile strength ≥ 25,000 psi, elongation ≥ 5%), **do not anneal after this step**, as annealing would lower strength.
---
### **Step 5: Check Properties after Cold Working**
- **Cold Work:** Increases strength, reduces ductility.
- **Annealing:** Recovers ductility, reduces strength.
- After the final reduction, we want the material to be in a strain-hardened (cold-worked) condition to have high strength, but not too much so it still maintains at least 5% elongation.
#### **Typical Properties of 3105 Aluminum:**
- As-rolled (cold-worked) 3105-H18:
- Tensile strength: ~28,000 psi
- Elongation: ~2-5%
- 3105-O (annealed):
- Tensile strength: ~16,000 psi
- Elongation: ~20%
**So, with a 50% cold reduction in the final step, you are likely to meet the minimum required properties.**
---
### **Step 6: Process Summary**
1. **Step 1:** Cold work 3.0 in → 0.6 in (80% reduction)
2. **Step 2:** Anneal at appropriate temperature for 3105 Al (e.g., ~350–400°C)
3. **Step 3:** Cold work 0.6 in → 0.3 in (50% reduction)
4. **Step 4:** Do **not** anneal after final step to retain strength.
---
### **Step 7: Hot Working Alternative**
If **hot working** is possible for the initial deformation, you could:
- **Hot work** the plate from 3.0 in to 0.6 in (or even directly to 0.3 in if possible).
- Hot working does not strain harden the material as much, so it remains ductile and easier to work.
- **Cold work** only the final pass (0.6 in → 0.3 in, 50% reduction) to achieve the desired strength.
- This makes the process easier and reduces the need to anneal between steps.
---
## **Final Answer (Summary Table)**
| Step | Operation | Thickness (in) | % Reduction | Anneal? |
|------|---------------------|----------------|-------------|-----------|
| 1 | Cold work | 3.0 → 0.6 | 80% | No |
| 2 | Anneal | 0.6 | — | Yes |
| 3 | Cold work | 0.6 → 0.3 | 50% | No |
- This sequence achieves the desired thickness and mechanical properties (≥25,000 psi strength, ≥5% elongation).
**If hot working is possible for the first reduction:**
- Hot work 3.0 in → 0.6 in (or 0.3 in)
- Cold work only the final step to 0.3 in
- No intermediate anneal needed
---
### **Conclusion**
- **Cold work–anneal–cold work** is the best route if constrained to cold working.
- **Hot working** is more efficient for large thickness reductions, followed by a final cold work for property control.
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