Give step-by-step solution with explanation and final answer:
Act like a helpful tutor and exlain me :
A portable bucket elevator for transporting sand is to be driven by a single
-
cylinder internal combustion engine operating at a speed of
1
4
0
0
rpm
,
using a B
-
section V
-
belt. The drive pulley and driven pulley each have a pitch diameter of
5
.
0
0
in
.
If the bucket elevator is to lift two tons per minute
(
4
0
0
0
lb
/
min
)
of sand to a height of
1
5
ft
,
continuously for
1
0
hours per workday, and if friction losses in the elevator are approximately
1
5
percent of the operating power, how many working days until failure would you estimate for the B
-
section belt if it has a gauge length of
5
9
.
8
inches
(
B
-
Belt
5
9
)
?
Question:
Give step-by-step solution with explanation and final answer:
Act like a helpful tutor and exlain me :
A portable bucket elevator for transporting sand is to be driven by a single
-
cylinder internal combustion engine operating at a speed of
1
4
0
0
rpm
,
using a B
-
section V
-
belt. The drive pulley and driven pulley each have a pitch diameter of
5
.
0
0
in
.
If the bucket elevator is to lift two tons per minute
(
4
0
0
0
lb
/
min
)
of sand to a height of
1
5
ft
,
continuously for
1
0
hours per workday, and if friction losses in the elevator are approximately
1
5
percent of the operating power, how many working days until failure would you estimate for the B
-
section belt if it has a gauge length of
5
9
.
8
inches
(
B
-
Belt
5
9
)
?
This is AI generated Response.
Asked by: manish kumar
Created at: 2025-09-14 14:30:33
Final Answer:
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# Step-by-Step Solution: Belt Life for Bucket Elevator
Let's break down and solve the problem step-by-step.
---
## **Given Data**
- **Engine Speed**: \( 1400\, \text{rpm} \)
- **V-belt type**: B-section
- **Pulley Pitch Diameters**: \( 5.00\, \text{in} \) (both drive and driven)
- **Load (Sand Lifted)**: \( 4000\, \text{lb/min} \)
- **Lift Height**: \( 15\, \text{ft} \)
- **Operation Time**: \( 10\, \text{hours/day} \)
- **Friction Losses**: \( 15\% \) of operating power
- **Belt Gauge Length**: \( 59.8\, \text{in} \) (B-59)
---
## **Step 1: Calculate Power Required to Lift Sand**
Work done per minute:
\[
\text{Work} = \text{Weight} \times \text{Height}
\]
\[
= 4000\, \text{lb} \times 15\, \text{ft} = 60,\!000\, \text{ft}\cdot\text{lb/min}
\]
Power in horsepower (\(1\, \text{hp} = 33,000\, \text{ft}\cdot\text{lb/min}\)):
\[
\text{Power (hp)} = \frac{60,000}{33,000} \approx 1.82\, \text{hp}
\]
---
## **Step 2: Account for Friction Losses**
Operating power must include friction losses:
\[
\text{Total Power} = \frac{\text{Required Power}}{1 - \text{Friction Loss Fraction}}
\]
\[
= \frac{1.82}{1 - 0.15} = \frac{1.82}{0.85} \approx 2.14\, \text{hp}
\]
So, **the belt must transmit 2.14 hp continuously**.
---
## **Step 3: Belt Speed Calculation**
The pitch diameter, \( D = 5.00\, \text{in} \).
Convert to feet:
\[
D = 5.00\, \text{in} \times \frac{1\, \text{ft}}{12\, \text{in}} = 0.417\, \text{ft}
\]
Belt speed (ft/min):
\[
V = \pi D N
\]
\[
= \pi \times 0.417\, \text{ft} \times 1400\, \text{rpm}
\]
\[
= 3.1416 \times 0.417 \times 1400 \approx 1,832\, \text{ft/min}
\]
---
## **Step 4: Check Belt Specification (B-Section, 59.8 in Gauge Length)**
### **Find Allowable HP Rating for B-Section Belt**
From standard V-belt tables (e.g., Gates, Browning):
- **B-section, 5" pulley, 1400 rpm**:
- Power rating per belt: ~2.2 hp (ranges from 2.0–2.5 hp depending on manufacturer)
- **B-59 (59.8")**: Standard, within service factor range.
**Since the required power is 2.14 hp, one B-section belt is sufficient.**
---
## **Step 5: Estimate Belt Life**
### **Find Expected Life for B-Section V-Belt**
- Under full rated load, **B-section V-belts typically last 2,500–3,000 hours** (per Gates or other manufacturer catalogs), assuming proper tensioning and alignment.
- Real-world factors (dust, heat, misalignment) may reduce this. Let’s use the conservative value: **2,500 hours**.
---
## **Step 6: Convert Belt Life to Working Days**
Each workday: 10 hours
\[
\text{Working days to failure} = \frac{2,500\, \text{hours}}{10\, \text{hours/day}} = 250\, \text{days}
\]
---
## **Step 7: Final Answer**
### **Summary Table**
| Step | Value/Result |
|----------------------|----------------------------|
| Power required | 1.82 hp |
| Power with friction | 2.14 hp |
| Belt speed | 1,832 ft/min |
| Belt type/length | B-section, 59.8 in |
| Rated belt life | 2,500 hours |
| Working days to fail | **250 days** |
---
## **Final Answer**
> **The B-section belt (B-59) will last approximately 250 working days before failure under the specified operating conditions.**
---
## **Notes**
- Actual life can vary depending on tension, alignment, environment (sand/dust), and maintenance.
- Check the manufacturer's catalog for exact ratings and use a service factor for harsh conditions if needed.
---
**If you have the catalog or manufacturer's data, we can refine the estimate further.**
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