VIPSolutionsGive step-by-step solution with explanation and final answer: A conveyor system is connected to a load cell that outputs a voltage proportional to the weight on the belt. When empty, the load cell outputs 0 V , and a weight of 6 0 0 Kg produces 6 V . Write a program in PLC that will measure the weight when an input sensor ( S ) becomes active. If the weight is between 2 5 0 Kg and 3 5 0 Kg , tum ON alarm output ( A 1 ) . If the weight is between 3 5 0 Kg and 5 0 0 Kg , turn ON alarm output ( A 2 ) .
Question:
Give step-by-step solution with explanation and final answer: A conveyor system is connected to a load cell that outputs a voltage proportional to the weight on the belt. When empty, the load cell outputs 0 V , and a weight of 6 0 0 Kg produces 6 V . Write a program in PLC that will measure the weight when an input sensor ( S ) becomes active. If the weight is between 2 5 0 Kg and 3 5 0 Kg , tum ON alarm output ( A 1 ) . If the weight is between 3 5 0 Kg and 5 0 0 Kg , turn ON alarm output ( A 2 ) .
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Asked by: Abhishek
Created at: 2025-09-22 22:58:47
Asked by: Abhishek
Created at: 2025-09-22 22:58:47
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# Step-by-Step Solution
## 1. Understanding the Load Cell Scaling
- **Known Points:**
- 0 V ⇒ 0 Kg
- 6 V ⇒ 600 Kg
- **Proportionality:**
This is a linear relationship:
\[
\text{Weight (Kg)} = \frac{\text{Voltage (V)}}{6} \times 600 = \text{Voltage (V)} \times 100
\]
So,
\[
\text{Weight (Kg)} = \text{Voltage (V)} \times 100
\]
\[
\text{Voltage (V)} = \frac{\text{Weight (Kg)}}{100}
\]
## 2. Problem Requirements
- **Input:** Sensor \( S \) (detects item)
- **Analog Input:** Load cell voltage (0-6 V)
- **Outputs:**
- \( A_1 \): ON if \( 250 \leq \text{Weight} < 350 \) Kg
- \( A_2 \): ON if \( 350 \leq \text{Weight} < 500 \) Kg
## 3. PLC Logic Outline
### **Variables**
| Symbol | Meaning |
|--------|------------------|
| S | Start sensor |
| AI | Analog input |
| A1 | Alarm output 1 |
| A2 | Alarm output 2 |
### **Step 1: Read Analog Input**
Assume analog value is read as voltage (0–6V) into variable `AI`.
### **Step 2: Convert Voltage to Weight**
```plaintext
Weight = AI * 100 // AI in Volts, Weight in Kg
```
### **Step 3: Check Ranges for Alarms**
- For \( 250 \leq \text{Weight} < 350 \), set A1 = 1
- For \( 350 \leq \text{Weight} < 500 \), set A2 = 1
### **Step 4: PLC Pseudocode**
```plaintext
IF S == 1 THEN
Weight := AI * 100
IF (Weight >= 250) AND (Weight < 350) THEN
A1 := 1
ELSE
A1 := 0
END_IF
IF (Weight >= 350) AND (Weight < 500) THEN
A2 := 1
ELSE
A2 := 0
END_IF
ELSE
A1 := 0
A2 := 0
END_IF
```
## 4. Example in Structured Text (IEC 61131-3)
```pascal
IF S THEN
Weight := AI * 100.0;
IF (Weight >= 250.0) AND (Weight < 350.0) THEN
A1 := TRUE;
ELSE
A1 := FALSE;
END_IF;
IF (Weight >= 350.0) AND (Weight < 500.0) THEN
A2 := TRUE;
ELSE
A2 := FALSE;
END_IF;
ELSE
A1 := FALSE;
A2 := FALSE;
END_IF;
```
## 5. Final Answer (Summary)
- **Weight Calculation:**
\( \text{Weight (Kg)} = \text{AI (V)} \times 100 \)
- **Alarm Logic:**
- \( \text{If } 250 \leq \text{Weight} < 350 \): set \( A_1 \) ON
- \( \text{If } 350 \leq \text{Weight} < 500 \): set \( A_2 \) ON
- **PLC Program Structure:**
1. When sensor \( S \) is active, read analog input.
2. Compute weight.
3. Set alarms according to the ranges above.
---
**Diagram (Optional):**
*Flowchart showing sensor input, analog read, weight calculation, and alarm outputs.*
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**This fulfills all requirements of the problem with correct scaling, logic, and program structure.**
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