Give step-by-step solution with explanation and final answer:eins Afncionsghen in canonical, -50 267491113.18 225 NEA TS 93. Spy th cin ing rs der Varale ered ip VE. wo J — El
Question:
Give step-by-step solution with explanation and final answer:
eins
Afncionsghen in canonical, -50 267491113.18 225 NEA TS 93.
Spy th cin ing rs der Varale ered ip VE. wo
J — El
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Asked by: Aman
Created at: 2025-09-26 07:56:18
Asked by: Aman
Created at: 2025-09-26 07:56:18
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# Solution to Question 1
Given function in canonical form:
\[
F = \sum m(,2,6,7,8,9,11,13,18,22,25,28,30) + \sum d(1,4,5,17,19,31)
\]
where \( \sum m \) are minterms and \( \sum d \) are don't cares.
Let's proceed step-by-step:
---
## **Step 1: Identify Number of Variables**
The highest index in the minterms/don't cares is 31, which means **5 variables** (\(2^5 = 32\)):
Let variables be: \( A, B, C, D, E \) ( = MSB, E = LSB).
---
## 2: List Out Minterms and Don't Cares**
- **Minterms:** , 2, 6, 7, 8, 9, 11, 13, 18, 22, 25, 28, 30
- **Don't Cares:** 1, 4, 5, 17, 19, 31
---
## **Step 3: Draw the First Order Variable Entered Map (VEM)**
Let's use **A** as the first-order entered variable. We'll create a 4-variable K-map for \(B, C, D, E\), with two maps: one for \(A=\) and one for \(A=1\).
### **Step 3a: Fill the K-Map**
#### For \(A=\) (minterms –15):
- Minterms: , 2, 6, 7, 8, 9, 11, 13
- Don't Cares: 1, 4, 5
#### For \(A=1\) (minterms 16–31):
- Minterms: 18, 22, 25, 28, 30
- Don't Cares: 17, 19, 31
---
### **Step 3b: Draw K-Maps**
#### Map for \(A=\) (\(m(\) to \(m(15)\)):
| | 00 | 01 | 11 | 10 |
|------|----|----|----|----|
| **00** | 1 | DC | | 1 |
| **01** | DC | | 1 | DC |
| **11** | | 1 | 1 | |
| **10** | 1 | 1 | | |
#### Map for \(A=1\) (\(m(16)\) to \(m(31)\)):
| | 00 | 01 | 11 | 10 |
|------|----|----|----|----|
| **00** | | DC | | |
| **01** | DC | 1 | | DC |
| **11** | | 1 | DC | |
| **10** | 1 | | 1 | |
(**Fill in each cell using binary representation; let me know if you need full K-map filling details.**)
---
## **Step 4: Simplify Using Groups**
### **For \(A=\):**
Find largest groups (use don't cares where possible):
- **Group 1:** (m6, m7, m14, m15): \(B=1, D=1\) for \(A=\)
- **Group 2:** (m2, m3, m6, m7): \(C=1, D=1\) for \(A=\)
- **Group 3:** (m8, m9, m10, m11): \(B=, C=\) for \(A=\)
### **For \(A=1\):**
- **Group 1:** (m22, m23, m30, m31): \(C=1, E=\) for \(A=1\)
- **Group 2:** (m25, m24, m28, m29): \(B=, D=\) for \(A=1\)
---
## **Step 5: Write Simplified Expression**
Combine the groups:
\[
F = A' [B D + C D + B' C'] + A [C E' + B' D']
\]
---
## **Step 6: Implement Using NAND Gates Only**
Convert each AND, OR, and NOT into NAND equivalents.
### **Step 6a: Express in terms of AND, OR, NOT**
\[
F = A' [(B D) + (C D) + (B' C')] + A [(C E') + (B' D')]
\]
### **Step 6b: Implement NAND equivalents**
- \(X \cdot Y = (X \text{ NAND } Y)'\) (use double NAND for AND)
- \(X + Y = (X' \cdot Y')' = (X \text{ NAND } X) \text{ NAND } (Y \text{ NAND } Y)\)
- \(X' = X \text{ NAND } X\)
#### **Rewrite**
Let’s convert each term into NAND logic.
---
## **Final Simplified Expression**
\[
\boxed{F = A' [B D + C D + B' C'] + A [C E' + B' D']}
\]
### **NAND Implementation (Block Diagram Suggestion)**
1. **Inverters:** (using NAND gates)
- \(A' = A \text{ NAND } A\)
- \(B' = B \text{ NAND } B\)
- \(C' = C \text{ NAND } C\)
- \(E' = E \text{ NAND } E\)
- \(D' = D \text{ NAND } D\)
2. **ANDs:** (using NAND gates)
- \(B D = (B \text{ NAND } D)'\)
- \(C D = (C \text{ NAND } D)'\)
- \(B' C' = (B' \text{ NAND } C')'\)
- \(C E' = (C \text{ NAND } E')'\)
- \(B' D' = (B' \text{ NAND } D')'\)
3. **ORs:** (using NAND gates)
- \([B D + C D + B' C'] = ((B D)' \text{ NAND } (C D)') \text{ NAND } ((B' C')')\)
- \([C E' + B' D'] = ((C E')' \text{ NAND } (B' D')')\)
4. **Combine with A and A':**
- \(A' \text{ AND } [B D + C D + B' C']\)
- \(A \text{ AND } [C E' + B' D']\)
5. **Final OR:**
- Combine outputs from steps above using NAND-based OR.
---
### **Summary Table**
| Step | Logic Expression | NAND Equivalent |
|------|------------------|----------------|
| NOT | \(X'\) | \(X \text{ NAND } X\) |
| AND | \(X \cdot Y\) | \((X \text{ NAND } Y) \text{ NAND } (X \text{ NAND } Y)\) |
| OR | \(X + Y\) | \((X' \text{ NAND } Y')\) |
---
## **Final Answers**
### **a) Simplified Function**
\[
\boxed{F = A' [B D + C D + B' C'] + A [C E' + B' D']}
\]
### **b) Implement using NAND gates only**
- Use the above logic, replacing every NOT, AND, OR with NAND equivalents as shown.
- Draw the circuit as a block diagram with each step in NAND logic (details as above).
---
**If you’d like a full step-by-step K-map filling and exact NAND gate diagram, let me know!**
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