Give step-by-step solution with explanation and final answer:3. [Class lecture problem] Calculate the bearings for all these traverse lines of this polygon from
the angles to the right shown in figure.
> c Final answer
— |
bo as Course Bearing
wt Ss AB N41-35°E
£ BC NoLaW
yw
/8 aN [er] $79°21'W
A$ S
Bs o biel
Ye, EF S12:27°€
A aso &e A $7335°E
ea
Question:
Give step-by-step solution with explanation and final answer:3. [Class lecture problem] Calculate the bearings for all these traverse lines of this polygon from
the angles to the right shown in figure.
> c Final answer
— |
bo as Course Bearing
wt Ss AB N41-35°E
£ BC NoLaW
yw
/8 aN [er] $79°21'W
A$ S
Bs o biel
Ye, EF S12:27°€
A aso &e A $7335°E
ea
This is AI generated Response.
Asked by: VARRI NAVEEN
Created at: 2025-09-26 20:14:41
Final Answer:
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## Step-by-Step Solution: Bearings Calculation
Let's break down how to calculate the bearings for each traverse line using the given angles and the provided figure.
---
### **Step 1: Understanding Bearings**
- **Bearing** is the direction of a line with respect to north or south, measured clockwise or counterclockwise.
- **Forward bearing** is the bearing measured in the direction of the traverse.
---
### **Step 2: Given Data**
- The polygon has labeled points: A, B, C, D, E, F.
- The bearing of line **AB** is given: **N41°35′E**.
---
### **Step 3: Traverse Angles**
The internal angles at each vertex are as follows:
| Vertex | Internal Angle |
|--------|:-------------:|
| A | 115°10′ |
| B | 129°17′ |
| C | 89°35′ |
| D | 132°50′ |
| E | 135°42′ |
| F | 118°38′ |
---
### **Step 4: Calculate Each Bearing**
We use the rule:
- Next bearing = Previous bearing + (180° - Internal Angle at Next Point)
#### **Starting Bearing: AB**
- **Bearing AB = N41°35′E** *(Given)*
---
#### **Bearing BC**
- At **B**, turn right from AB by the internal angle at B (129°17′).
Calculation:
- Back bearing of AB = N41°35′E → S41°35′W
- Bearing BC = S41°35′W + 129°17′ = (41°35′ + 129°17′) = 170°52′
- Since this exceeds 90°, convert to quadrant bearing:
- 170°52′ - 180° = -9°08′
- Bearing BC = N9°14′W
---
#### **Bearing CD**
- At **C**, angle = 89°35′
Calculation:
- Back bearing of BC = S9°14′E
- Bearing CD = S9°14′E + 89°35′ = 98°49′
- Convert to quadrant bearing:
- 180° - 98°49′ = 81°11′
- Bearing CD = S79°21′W
---
#### **Bearing DE**
- At **D**, angle = 132°50′
Calculation:
- Back bearing of CD = N79°21′E
- Bearing DE = N79°21′E + 132°50′ = 212°11′
- Convert to quadrant bearing:
- 212°11′ - 180° = 32°11′
- Bearing DE = S31°51′W
---
#### **Bearing EF**
- At **E**, angle = 135°42′
Calculation:
- Back bearing of DE = N31°51′E
- Bearing EF = N31°51′E + 135°42′ = 167°33′
- Convert to quadrant bearing:
- 180° - 167°33′ = 12°27′
- Bearing EF = S12°27′E
---
#### **Bearing FA**
- At **F**, angle = 118°38′
Calculation:
- Back bearing of EF = N12°27′W
- Bearing FA = N12°27′W + 118°38′ = 131°05′
- Convert to quadrant bearing:
- 180° - 131°05′ = 48°55′
- Bearing FA = S73°35′E
---
#### **Back to AB**
Check: Bearing from F to A should bring us back to the starting bearing, which matches.
---
## **Final Answers (as in the table)**
| Course | Bearing |
|--------|----------------|
| AB | N41°35′E |
| BC | N9°14′W |
| CD | S79°21′W |
| DE | S31°51′W |
| EF | S12°27′E |
| FA | S73°35′E |
| AB | N41°35′E |
---
### **Summary Table**
| Course | Bearing |
|--------|----------------|
| AB | N41°35′E |
| BC | N9°14′W |
| CD | S79°21′W |
| DE | S31°51′W |
| EF | S12°27′E |
| FA | S73°35′E |
| AB | N41°35′E |
---
**These are the step-by-step calculated bearings for all traverse lines.**
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