How can the inverse o f the Hessian matrix for the function f ( x ) = 2 x 1 2 - 2 x 2 2 - x 1 x 2 b e approximated b y a positive - definite matrix
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How can the inverse o f the Hessian matrix for the function f ( x ) = 2 x 1 2 - 2 x 2 2 - x 1 x 2 b e approximated b y a positive - definite matrix
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Asked by: Pradeep Rajora
Created at: 2025-09-18 01:26:23
Asked by: Pradeep Rajora
Created at: 2025-09-18 01:26:23
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# Problem Overview
Given the function:
\[
f(x) = 2x_1^ - 2x_2^ - x_x_2
]
we are interested in the Hessian matrix \( H \), its inverse \( H^{-1} \), and how to approximate \( H^{-1} \) by a **positive-definite matrix**.
---
# 1. Compute the Hessian Matrix
The Hessian \( H \) is the matrix of second derivatives:
\[
H =
\begin{bmatrix}
\frac{\partial^2 f}{\partial x_1^2} & \frac{\partial^2 f}{\partial x_1 \partial x_2} \\
\frac{\partial^2 f}{\partial x_2 \partial x_1} & \frac{\partial^2 f}{\partial x_2^2}
\end{bmatrix}
\]
Calculate derivatives:
- \( f_{x_1x_1} = \frac{\partial^2 f}{\partial x_1^2} = 4 \)
- \( f_{x_2x_2} = \frac{\partial^2 f}{\partial x_2^2} = -4 \)
- \( f_{x_1x_2} = f_{x_2x_1} = \frac{\partial^2 f}{\partial x_1 \partial x_2} = -1 \)
So,
\[
H =
\begin{bmatrix}
4 & -1 \\
-1 & -4
\end{bmatrix}
\]
---
# 2. Inverse of the Hessian
For a \( 2 \times 2 \) matrix:
\[
A = \begin{bmatrix} a & b \\ c & d \end{bmatrix} \implies
A^{-1} = \frac{1}{ad - bc} \begin{bmatrix} d & -b \\ -c & a \end{bmatrix}
\]
So, for \( H \):
- \( a = 4, b = -1, c = -1, d = -4 \)
- Determinant: \( (4)(-4) - (-1)(-1) = -16 - 1 = -17 \)
\[
H^{-1} = \frac{1}{-17}
\begin{bmatrix}
-4 & 1 \\
1 & 4
\end{bmatrix}
=
\begin{bmatrix}
4/17 & -1/17 \\
-1/17 & -4/17
\end{bmatrix}
\]
---
# 3. Is \( H^{-1} \) Positive Definite?
A symmetric matrix is positive definite if all its eigenvalues are positive. However, since the determinant is negative (\( -17 \)), \( H \) and its inverse are both **indefinite** (have both positive and negative eigenvalues).
---
# 4. Approximating \( H^{-1} \) by a Positive-Definite Matrix
To use \( H^{-1} \) in optimization algorithms that require positive-definite matrices (like quasi-Newton methods), you can:
## 4.1. Diagonal Approximation
Keep only positive diagonal entries:
\[
M = \begin{bmatrix}
|4/17| & 0 \\
0 & |4/17|
\end{bmatrix}
= \begin{bmatrix}
4/17 & 0 \\
0 & 4/17
\end{bmatrix}
\]
## 4.2. Modified Identity Scaling
Set \( M = \alpha I \), where \( \alpha > 0 \) and \( I \) is the identity matrix. Choose \( \alpha \) to approximate the scale of \( H^{-1} \):
\[
M = \frac{4}{17} I
\]
## 4.3. Shifted/Regularized Inverse
Add a positive multiple of the identity to \( H \) before inverting:
\[
M = (H + \lambda I)^{-1}, \quad \lambda > | \text{min eigenvalue of } H |
\]
Choose \( \lambda \) large enough so \( H + \lambda I \) is positive definite.
## 4.4. Spectral Decomposition and Truncation
- Diagonalize \( H^{-1} \): \( H^{-1} = Q \Lambda Q^T \)
- Set all negative eigenvalues in \( \Lambda \) to a small positive value \( \epsilon \)
- Reconstruct \( M = Q \Lambda_+ Q^T \) (where \( \Lambda_+ \) has only positive entries)
---
# 5. Summary
To approximate the (indefinite) \( H^{-1} \) by a positive-definite matrix:
- Use a diagonal positive matrix based on \( H^{-1} \)'s positive entries
- Use a scaled identity matrix
- Add a regularization term before inversion
- Use spectral truncation to force positive eigenvalues
The choice depends on your application and desired trade-off between accuracy and positive-definiteness.
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