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Act like a helpful tutor and exlain me :Draw the product of the reaction shown below. Ignore inorganic byproducts. [e) OH [e] Na2Cr207 Acetone, H2S04 PY ' ] ' ' ' ' H Drawing ' fH H Atoms, Bonds a and Rings Charges I | I i | N S I NI BPN u NA | De NE EPSON Re nn Sw” Mn, | ZN

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Act like a helpful tutor and exlain me :Uploaded ImageDraw the product of the reaction shown below. Ignore inorganic byproducts. [e) OH [e] Na2Cr207 Acetone, H2S04 PY ' ] ' ' ' ' H Drawing ' fH H Atoms, Bonds a and Rings Charges I | I i | N S I NI BPN u NA | De NE EPSON Re nn Sw” Mn, | ZN

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Asked by: Alok Kumar
Created at: 2026-02-01 04:33:40

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## Explanation of the Reaction Let's break down what is happening step by step: ### 1. **Reactant Identification** The starting molecule is **1,2-dihydroxyanthracene** (also known as anthracene-1,2-diol). - It has two hydroxyl (-OH) groups attached to adjacent carbons on the anthracene ring system. ### 2. **Reagents** - **Na₂Cr₂O₇** (sodium dichromate) in **acidic solution (H₂SO₄)** is a **strong oxidizing agent**. - The solvent is **acetone**, which doesn't interfere with the oxidation. ### 3. **Type of Reaction** - **Oxidation of Diols:** Sodium dichromate will **oxidize both hydroxyl groups (-OH)** to carbonyl groups (=O). - In aromatic diols (like this), both -OH groups on adjacent carbons are oxidized to **ketones** (C=O), and if possible, a quinone structure is formed. ### 4. **Product** - The product is **anthraquinone** (specifically, 1,2-anthraquinone). - Both -OH groups are converted to **C=O** groups on the aromatic ring. ### 5. **Structure Check** - The image on the right shows a molecule where two ketone (=O) groups are attached to the anthracene ring at the same positions where the -OH groups were originally located. - This is correct! The product is a **quinone** structure. --- ## **Summary Table** | Step | What Happens? | |---------------------|---------------------------------------------------| | Starting material | 1,2-dihydroxyanthracene (anthracene-1,2-diol) | | Reagent | Na₂Cr₂O₇, H₂SO₄ (strong oxidizer) | | Reaction | Oxidation of both -OH groups to =O | | Product | 1,2-anthraquinone (quinone structure) | --- ## **Why This Happens** - **Na₂Cr₂O₇/H₂SO₄** is a strong oxidizer, and in aromatic systems, it often converts diols to quinones. - The aromaticity is restored after oxidation, stabilizing the product. --- ## **Visual Explanation** - **Left:** Anthracene ring with two -OH groups (adjacent) - **Right (Product):** Anthracene ring with two =O groups (adjacent; forming a quinone) --- **In summary:** The reaction converts 1,2-dihydroxyanthracene to 1,2-anthraquinone by oxidizing the hydroxyl groups to ketones (C=O), using sodium dichromate and acid. If you have any more questions or want to see the stepwise mechanism, let me know!

Question:

How is boiling point affected by elevation? A distillate was collected between 7 8 - 8 2 ° C at sea level. The reported boiling point was 8 0 ° C . Comment on the correctness of this report. Explain the effects of polarity of molecules on boiling point. The normal boiling point of toluene ( at 7 6 0 torr ) is 1 1 0 ° C . Use the boiling point nomograph ( Figure ID - 1 ) to determine the boiling point of toluene at 6 0 0 torr. A liquid boils at 1 0 2 ° C in a lab in Colorado Springs, where the ambient pressure is 6 0 0 torr. What is the corrected boiling point of the liquid?

This is AI generated Response.
Asked by: Alok Kumar
Created at: 2026-02-04 05:50:55

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# Boiling Point and Elevation Effects ## 1. **Boiling Point at Different Elevations** - **Effect of Elevation**: As elevation increases, atmospheric pressure decreases, resulting in a lower boiling point for liquids. - **Example**: At sea level (760 torr), water boils at 100°C. In higher elevations, water will boil at a temperature lower than 100°C. ## 2. **Assessment of Distillation Report** - **Reported Temperature**: A distillate was collected between 78-82°C with a reported boiling point of 80°C. - **Comment on Correctness**: - If this report was made at sea level, it seems reasonable since the boiling point is within the collected range. - If made at higher elevation (lower pressure), the boiling point would be lower, making the report potentially inaccurate. ## 3. **Effects of Polarity on Boiling Point** - **Polarity and Boiling Point**: - Polar molecules generally have higher boiling points than non-polar molecules due to stronger intermolecular forces (like hydrogen bonding and dipole-dipole interactions). - Non-polar molecules interact primarily through London dispersion forces, which are weaker. ## 4. **Boiling Point of Toluene at 600 Torr** - **Normal Boiling Point of Toluene**: 110°C at 760 torr. - **Using a Nomograph**: - It typically shows that the boiling point decreases as pressure decreases. - At 600 torr, the boiling point of toluene can be estimated to be approximately **95°C**. ## 5. **Corrected Boiling Point of a Liquid at 600 Torr** - **Observed Boiling Point**: 102°C at 600 torr. - **Corrected Boiling Point**: To determine the corrected boiling point at standard pressure (760 torr), you would typically: - Compare the boiling points at the two pressures. - For a more precise correction, you may use a boiling point elevation equation or a graph/nomograph. - **Conclusion**: The boiling point at 760 torr would be higher than observed, indicating that 102°C is indeed lower than the standard boiling point. --- ## **Summary** - Boiling point decreases with elevation due to lower pressure. - The correctness of boiling point reports depends on the measurement conditions (elevation). - Polarity influences boiling points, with polar molecules having higher boiling points. - The boiling point of toluene decreases at lower pressures, and corrections can be made for observed boiling points at different pressures.

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