Certainly! I see that you want each step to contain only one equal sign per line. Here’s the step-by-step solution rewritten as you requested: --- ### **Step 1:** Write the formula for the final point force of a pile: - \( Q_p = qp \times A_p \) Where: - \( qp \) = ultimate resistance point \((kN/m^2)\) - \( A_p \) = cross-sectional area of the pile tip \((m^2)\) --- ### **Step 2:** The ultimate resistance point in sand (Briand & Tucker method): - \( qp = C_N \times SPT \times \gamma' \) Given: - \( C_N = 4.5 \) (empirical constant for dense sand) - \( SPT = 22 \) (Standard Penetration Test value) - \( \gamma' = 10 \, kN/m^3 \) (effective unit weight of soil) Calculate \( qp \): - \( qp = 4.5 \times 22 \times 10 \) - \( qp = 990 \, kN/m^2 \) --- ### **Step 3:** Calculate the cross-sectional area at the pile tip: - \( A_p = \frac{\pi}{4} \times d^2 \) Given: - \( d = 0.3 \, m \) (diameter of pile) Substitute the value: - \( A_p = \frac{\pi}{4} \times (0.3)^2 \) - \( A_p = \frac{\pi}{4} \times 0.09 \) - \( A_p = 0.07069 \, m^2 \) --- ### **Step 4:** Calculate \( Q_p \): - \( Q_p = qp \times A_p \) - \( Q_p = 990 \times 0.07069 \) - \( Q_p = 69.98 \, kN \) --- ### **Final Answer:** - \( Q_p = 69.98 \, kN \) --- If you need further breakdown or have more questions, let me know!