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Let's discuss the changes applied to the atoms present in the structure to complete the Lewis structure. Atom 1 (Carbon): Carbon has \(\mathrm{{4}}\)4 valence electrons. All \(\mathrm{{4}}\)4 electrons forms bonds and complete the octet of carbon. Atom 2 (oxygen): Oxygen has \(\mathrm{{6}}\)6 valence electrons. Two electrons forms two bonds leaving \(\mathrm{{4}}\)4 valence electrons which make its octet complete. The remaining \(\mathrm{{4}}\)4 valence electrons can be represented as two lone pairs on oxygen. Atom 3 (carbon): Carbon has \(\mathrm{{4}}\)4 valence electrons. Three electrons forms bond but it does not complete carbons octet. Only \(\mathrm{{7}}\)7 electrons are present for carbon making its octet incomplete. So, one positive charge on carbon will show lack of one electron in its octet completion, making it electron-deficient. Atom 4 (chlorine): Chlorine has \(\mathrm{{7}}\)7 valence electrons. One electrons forms a bond leaving 6 valence electrons which make its octet complete. The remaining \(\mathrm{{6}}\)6 valence electrons can be represented as \(\mathrm{{3}}\)3 lone pairs on chlorine. Atom 5 (oxygen): Oxygen has \(\mathrm{{6}}\)6 valence electrons, and only one is used in bonding. To complete its octet, it accepts an extra electron and carrying a negative charge making oxygen electron-rich. It has \(\mathrm{{3}}\)3 lone pairs of electrons. The complete Lewis structure has zero net charge. (humanize itto avoid ai detection)

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Let's discuss the changes applied to the atoms present in the structure to complete the Lewis structure. Atom 1 (Carbon): Carbon has \(\mathrm{{4}}\)4 valence electrons. All \(\mathrm{{4}}\)4 electrons forms bonds and complete the octet of carbon. Atom 2 (oxygen): Oxygen has \(\mathrm{{6}}\)6 valence electrons. Two electrons forms two bonds leaving \(\mathrm{{4}}\)4 valence electrons which make its octet complete. The remaining \(\mathrm{{4}}\)4 valence electrons can be represented as two lone pairs on oxygen. Atom 3 (carbon): Carbon has \(\mathrm{{4}}\)4 valence electrons. Three electrons forms bond but it does not complete carbons octet. Only \(\mathrm{{7}}\)7 electrons are present for carbon making its octet incomplete. So, one positive charge on carbon will show lack of one electron in its octet completion, making it electron-deficient. Atom 4 (chlorine): Chlorine has \(\mathrm{{7}}\)7 valence electrons. One electrons forms a bond leaving 6 valence electrons which make its octet complete. The remaining \(\mathrm{{6}}\)6 valence electrons can be represented as \(\mathrm{{3}}\)3 lone pairs on chlorine. Atom 5 (oxygen): Oxygen has \(\mathrm{{6}}\)6 valence electrons, and only one is used in bonding. To complete its octet, it accepts an extra electron and carrying a negative charge making oxygen electron-rich. It has \(\mathrm{{3}}\)3 lone pairs of electrons. The complete Lewis structure has zero net charge. (humanize itto avoid ai detection)

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Asked by: Alok Kumar Bind
Created at: 2025-08-31 06:00:04

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Absolutely! Let’s walk through how each atom’s electrons are arranged and discuss how the Lewis structure comes together in a more conversational way. --- **Atom 1: Carbon** Carbon naturally brings 4 valence electrons to the table. In this structure, it uses all 4 to make bonds with its neighboring atoms. This means carbon has achieved a full set of 8 electrons around it—its octet is complete, and it's nice and stable! --- **Atom 2: Oxygen** Oxygen starts with 6 valence electrons. Here, it uses 2 of those electrons to form two bonds (probably double bonded to carbon), and the other 4 electrons remain as two lone pairs. With these bonds and lone pairs, oxygen also has a complete octet. --- **Atom 3: Carbon** This carbon atom also starts with 4 valence electrons. However, in this structure, it only forms three bonds. That leaves it with only 6 electrons in its "circle" (since each bond gives it one more electron), so it falls short of a full octet. This makes the carbon electron-deficient, and as a result, it carries a positive charge in the structure. --- **Atom 4: Chlorine** Chlorine has 7 valence electrons. It forms a single bond (using one electron) and keeps the remaining 6 electrons as three lone pairs. With those, chlorine’s octet is filled, and it's content. --- **Atom 5: Oxygen** This oxygen starts with its usual 6 valence electrons, but here, it only forms one bond. To fill its octet (since the bond only adds one more electron), it actually picks up an extra electron, giving it a total of 7 electrons around it from its own and one from the negative charge it carries. So, it has three lone pairs, making it electron-rich and negatively charged. --- **Final Charge:** If you count up the charges—one positive from the electron-deficient carbon, and one negative from the oxygen with the extra electron—they cancel each other out. That means the overall Lewis structure is neutral, with no net charge. --- **Summary Table:** | Atom | Valence Electrons | Bonds Formed | Lone Pairs | Charge | |-----------|-------------------|--------------|------------|----------------| | Carbon 1 | 4 | 4 | 0 | 0 (octet) | | Oxygen 1 | 6 | 2 | 2 | 0 (octet) | | Carbon 2 | 4 | 3 | 0 | +1 (deficient) | | Chlorine | 7 | 1 | 3 | 0 (octet) | | Oxygen 2 | 6 (+1) | 1 | 3 | -1 (extra e-) | --- Let me know if you'd like a sketch of the Lewis structure or if anything needs more explanation!

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