Let's discuss the changes applied to the atoms present in the structure to complete the Lewis structure. Atom 1 (Carbon): Carbon has \(\mathrm{{4}}\)4 valence electrons. All \(\mathrm{{4}}\)4 electrons forms bonds and complete the octet of carbon. Atom 2 (oxygen): Oxygen has \(\mathrm{{6}}\)6 valence electrons. Two electrons forms two bonds leaving \(\mathrm{{4}}\)4 valence electrons which make its octet complete. The remaining \(\mathrm{{4}}\)4 valence electrons can be represented as two lone pairs on oxygen. Atom 3 (carbon): Carbon has \(\mathrm{{4}}\)4 valence electrons. Three electrons forms bond but it does not complete carbons octet. Only \(\mathrm{{7}}\)7 electrons are present for carbon making its octet incomplete. So, one positive charge on carbon will show lack of one electron in its octet completion, making it electron-deficient. Atom 4 (chlorine): Chlorine has \(\mathrm{{7}}\)7 valence electrons. One electrons forms a bond leaving 6 valence electrons which make its octet complete. The remaining \(\mathrm{{6}}\)6 valence electrons can be represented as \(\mathrm{{3}}\)3 lone pairs on chlorine. Atom 5 (oxygen): Oxygen has \(\mathrm{{6}}\)6 valence electrons, and only one is used in bonding. To complete its octet, it accepts an extra electron and carrying a negative charge making oxygen electron-rich. It has \(\mathrm{{3}}\)3 lone pairs of electrons. The complete Lewis structure has zero net charge. (humanize itto avoid ai detection)
Question:
Let's discuss the changes applied to the atoms present in the structure to complete the Lewis structure. Atom 1 (Carbon): Carbon has \(\mathrm{{4}}\)4 valence electrons. All \(\mathrm{{4}}\)4 electrons forms bonds and complete the octet of carbon. Atom 2 (oxygen): Oxygen has \(\mathrm{{6}}\)6 valence electrons. Two electrons forms two bonds leaving \(\mathrm{{4}}\)4 valence electrons which make its octet complete. The remaining \(\mathrm{{4}}\)4 valence electrons can be represented as two lone pairs on oxygen. Atom 3 (carbon): Carbon has \(\mathrm{{4}}\)4 valence electrons. Three electrons forms bond but it does not complete carbons octet. Only \(\mathrm{{7}}\)7 electrons are present for carbon making its octet incomplete. So, one positive charge on carbon will show lack of one electron in its octet completion, making it electron-deficient. Atom 4 (chlorine): Chlorine has \(\mathrm{{7}}\)7 valence electrons. One electrons forms a bond leaving 6 valence electrons which make its octet complete. The remaining \(\mathrm{{6}}\)6 valence electrons can be represented as \(\mathrm{{3}}\)3 lone pairs on chlorine. Atom 5 (oxygen): Oxygen has \(\mathrm{{6}}\)6 valence electrons, and only one is used in bonding. To complete its octet, it accepts an extra electron and carrying a negative charge making oxygen electron-rich. It has \(\mathrm{{3}}\)3 lone pairs of electrons. The complete Lewis structure has zero net charge. (humanize itto avoid ai detection)
Asked by: Alok Kumar Bind
Created at: 2025-08-31 06:00:04
Final Answer:
📢 Instructions:
- Ask anything relatd to above question only.
- For new Question goto :
VIPSolutions