Please provide an lovely images with couple(c) What is meant by the term “trans effect’? Describe the synthesis of 1 ce [PtCI(py)(NH3)Br] from [PtCl«]> and other reagents of your choice by utilizing the knowledge of “trans effect”. Show the sequence of reactions. (4)
Question:
Please provide an lovely images with couple
(c) What is meant by the term “trans effect’? Describe the synthesis of
1 ce
[PtCI(py)(NH3)Br] from [PtCl«]> and other reagents of your choice by utilizing
the knowledge of “trans effect”. Show the sequence of reactions. (4)
This is AI generated Response.
Asked by: Test User 100143
Created at: 2025-05-06 16:57:50
Asked by: Test User 100143
Created at: 2025-05-06 16:57:50
Final Answer:
Rendered
Raw Text
Did you like this answer?
Certainly! Here is the answer to your question:
---
### **Trans Effect:**
The **trans effect** is an effect observed in square planar complexes (especially of platinum(II)), where certain ligands can increase the rate of substitution of the ligand trans (opposite) to themselves. In other words, a ligand with a strong trans effect makes it easier for another ligand to replace the ligand opposite to it.
**Order of trans effect (from strongest to weakest):**
`CN⁻ > CO > NO₂⁻ > I⁻ > Br⁻ > Cl⁻ > py (pyridine) > NH₃ > H₂O`
---
### **Synthesis of [PtCl(py)(NH₃)Br] from [PtCl₄]²⁻:**
#### **Step 1: Starting Material**
- [PtCl₄]²⁻ (tetrachloroplatinate(II))
#### **Step 2: Substitution with NH₃**
Add ammonia (NH₃) to substitute one Cl⁻ ligand.
- **[PtCl₄]²⁻ + NH₃ → [PtCl₃(NH₃)]⁻ + Cl⁻**
NH₃ will replace a Cl⁻. Since Cl⁻ and NH₃ both have weak trans effect, the substitution can occur at any position.
#### **Step 3: Substitution with Pyridine (py)**
Add pyridine (py) to substitute another Cl⁻ ligand.
- **[PtCl₃(NH₃)]⁻ + py → [PtCl₂(py)(NH₃)] + Cl⁻**
Py has a stronger trans effect than NH₃, so it prefers to go trans to NH₃.
#### **Step 4: Substitution with Br⁻**
Add Br⁻ to substitute the Cl⁻ ligand trans to py (because py has a stronger trans effect than Cl⁻ or NH₃).
- **[PtCl₂(py)(NH₃)] + Br⁻ → [PtCl(py)(NH₃)Br] + Cl⁻**
---
### **Sequence of Reactions:**
1. **[PtCl₄]²⁻ + NH₃ → [PtCl₃(NH₃)]⁻ + Cl⁻**
2. **[PtCl₃(NH₃)]⁻ + py → [PtCl₂(py)(NH₃)] + Cl⁻**
3. **[PtCl₂(py)(NH₃)] + Br⁻ → [PtCl(py)(NH₃)Br] + Cl⁻**
---
### **Summary Table:**
| Step | Reactant | Reagent | Product |
|------|-------------------------------|-------------|-------------------------------|
| 1 | [PtCl₄]²⁻ | NH₃ | [PtCl₃(NH₃)]⁻ |
| 2 | [PtCl₃(NH₃)]⁻ | py | [PtCl₂(py)(NH₃)] |
| 3 | [PtCl₂(py)(NH₃)] | Br⁻ | [PtCl(py)(NH₃)Br] |
---
**Note:** The order of addition is crucial due to the trans effect. Adding py before Br⁻ ensures that Br⁻ will be placed trans to py, which is dictated by the stronger trans effect of pyridine compared to NH₃ or Cl⁻.
---
If you would like a reaction scheme or structural diagrams, let me know!
📢 Instructions:
- Ask anything relatd to above question only.
- For new Question goto :
VIPSolutions