Sure! Let's go through this-by-step in a clear and simple way, just like how you'd see it explained in a solution guide. --- ## Given Information - Total number of students: **60** - Number of students who got a **B**: **8** - The table shows the distribution of students by gender and their grades. | Gender | A | B | C | Total | |----------|----|----|----|--------| | Male | 19 | 2 | 14 | 35 | | Female | 4 | 6 | 15 | 25 | | **Total**| 23 | 8 | 29 | 60 | --- ## What we need to find - **Probability that a randomly chosen student did NOT get a B.** --- ## Step 1: Understanding the concept - The probability of an event happening is the number of favorable outcomes divided by the total number of outcomes. - Here, the **favorable outcomes** are students **who did NOT get a B**. - The **total outcomes** are all students, which is **60**. --- ## Step 2: Find the number of students who did **NOT** get a B - Total students: 60 - Students who got a B: 8 So, students who did **NOT** get a B = Total students - Students who got B \[ \text{Students who did NOT get B} = 60 - 8 = 52 \] --- ## Step 3: Calculate the probability - Probability that a student **did NOT** get a B = Number of students who did NOT get B / Total students \[ P(\text{not B}) = \frac{52}{60} \] - Simplify the fraction: \[ \frac{52}{60} = \frac{13}{15} \] --- ## **Final Answer:** \[ \boxed{ \text{Probability that a student did NOT get a B} = \frac{13}{15} } \] --- ## Summary: - Out of 60 students, 52 did not get a B. - The probability is \(\frac{13}{15}\), meaning there's a high chance that a randomly selected student didn't get a B.