✨ VIPSolutions

Let's clarify your question: you are likely referring to the **terminal points** on the unit circle that correspond to the angles \(\frac{\pi}{2}\), \(\pi\), \(\frac{3\pi}{2}\), and \(2\pi\). On the **unit circle**, the terminal point of an angle \(\theta\) is given by \((\cos\theta, \sin\theta)\). Let's compute each one: --- ### 1. \(\theta = \frac{\pi}{2}\) \[ (\cos{\frac{\pi}{2}}, \sin{\frac{\pi}{2}}) = (0, 1) \] --- ### 2. \(\theta = \pi\) \[ (\cos{\pi}, \sin{\pi}) = (-1, 0) \] --- ### 3. \(\theta = \frac{3\pi}{2}\) \[ \left(\cos{\frac{3\pi}{2}}, \sin{\frac{3\pi}{2}}\right) = (0, -1) \] --- ### 4. \(\theta = 2\pi\) \[ (\cos{2\pi}, \sin{2\pi}) = (1, 0) \] --- ## **Summary Table** | Angle (\(\theta\)) | Terminal Point \((x, y)\) | |------------------------|:-------------------------:| | \(\frac{\pi}{2}\) | \((0, 1)\) | | \(\pi\) | \((-1, 0)\) | | \(\frac{3\pi}{2}\) | \((0, -1)\) | | \(2\pi\) | \((1, 0)\) | --- **So, the terminal points are:** \[ \boxed{(0,1),\ (-1,0),\ (0,-1),\ (1,0)} \]